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Ivenika [448]
3 years ago
9

There are 8 different types of chips at Subway How many different ways can you choose 2 of them?

Mathematics
1 answer:
earnstyle [38]3 years ago
3 0

We have been given that there are 8 different types of chips at Subway. We are asked to find the number of different ways to choose 2 of them.

We will use combinations to solve our given problem.

Number of combinations of r objects chosen from n objects is given by C(n,r)=\frac{n!}{r!(n-r)!}

C(8,2)=\frac{8!}{2!(8-2)!}

C(8,2)=\frac{8\cdot 7\cdot 6!}{2\cdot 1\cdot 6!}

C(8,2)=\frac{8\cdot 7}{2}

C(8,2)=4\cdot 7

C(8,2)=28

Therefore, you can choose 2 of them in 28 different ways.

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For test point x = –2, the inequality is true.

For test point x = 0, the inequality is false.

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For test point x = 2, the inequality is false.

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Given expression is the inequality.

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Substitute x = –2 in the inequality.

$\frac{5 (-2)-3}{(-2-1)(-2+1) }=\frac{-13}{(-3)(-1) }

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For test point x = –2, the inequality is true.

Substitute x = 0 in the inequality.

$\frac{5 (0)-3}{(0-1)(0+1) }=\frac{-3}{(-1)(1) }

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For test point x = 0, the inequality is false.

Substitute x=\frac{4}{5} in the inequality.

$\frac{5 (\frac{4}{5} )-3}{((\frac{4}{5} )-1)((\frac{4}{5} )+1) }=\frac{1}{(-\frac{1}{5} )(\frac{9}{5} ) }

                            $=\frac{-25}{9 }

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For test point x=\frac{4}{5}, the inequality is true.

Substitute x = 2 in the inequality.

$\frac{5 (2)-3}{(2-1)(2+1) }=\frac{7}{(1)(3) }

                      $=\frac{7}{3 }

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For test point x = 2, the inequality is false.

Hence,

For test point x = –2, the inequality is true.

For test point x = 0, the inequality is false.

For test point x=\frac{4}{5}, the inequality is true.

For test point x = 2, the inequality is false.

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Answer:

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Step-by-step explanation:

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