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Paladinen [302]
3 years ago
13

Drag each tile to the table to multiply each row heading by each column heading

Mathematics
2 answers:
weeeeeb [17]3 years ago
4 0

Answer:

multiplication by d=> 2d^3, 11d^2, -4d

multiplication by -9=>-18d^2,-99d, 36

The answers are in order from left to right.

Step-by-step explanation:

mark me as brainliest plz

zloy xaker [14]3 years ago
4 0

Answer:

drag each result in the corresponding box according to the results

Step-by-step explanation:

Hello

The product of two or more powers of equal  base "a" is equal to the power of base  "a" with   exponent equal to the sum of the respective exponents.

a^{m}*a^{n} =a^{n+m}

Step 1

d*2d^{2}\\

d*2d^{2}=(2*1)d^{(2+1)}\\d*2d^{2}=2d^{3} \\

Step 2

-9*2d^{2}\\

-9*2d^{2}=(-9*2)d^{(2+0)}\\-9*2d^{2}=-18d^{2} \\

Step 3

d*11d\\

d*11d=(1*11)d^{(1+1)}\\11*d^{2}=11d^{2} \\

Step 4

-9 * 11d\\

-9 * 11d = (-9*11)d^{1+0}=-99 d

Step 5

d*-4=-4d

Step 6

-9*-4 = ( -*- ) (9*4)= 36

Step 7

Now, drag each result in the corresponding box .

Have a great day

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timofeeve [1]
(33/4) / (2/8)
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33/4 * 8/2 = 66/2 = 33...hmm...not an answer choice

let me try something..
(3 3/4) / (2/8) =
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15 <====possibly this one if ur problem is : (3 3/4) / (2/8)

5 0
3 years ago
Read 2 more answers
-3(n + 5) = 12<br> solve^
UNO [17]

Answer:

n= 1

Step-by-step explanation:

-3n + 15 =12

-15. -15

-3n= - 3

÷-3 ÷-3

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5 0
3 years ago
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mario62 [17]

<em>Good luck, you'll need it :)</em>

6 0
3 years ago
Your allowance increases by $2 every month. You started earning $20 per month. Write a formula to find how much allowance you wi
NemiM [27]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Express the quotient of z1 and z2 in standard form given that <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D%20-3%5Bcos%28%5C
Lesechka [4]

Answer:

Solution : -\frac{3}{4}-\frac{3}{4}i

Step-by-step explanation:

-3\left[\cos \left(\frac{-\pi }{4}\right)+i\sin \left(\frac{-\pi \:}{4}\right)\right]\:\div \:2\sqrt{2}\left[\cos \left(\frac{-\pi \:\:}{2}\right)+i\sin \left(\frac{-\pi \:\:\:}{2}\right)\right]

Let's apply trivial identities here. We know that cos(-π / 4) = √2 / 2, sin(-π / 4) = - √2 / 2, cos(-π / 2) = 0, sin(-π / 2) = - 1. Let's substitute those values,

\frac{-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right)}{2\sqrt{2}\left(0-1\right)i}

=-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right) ÷ 2\sqrt{2}\left(0-1\right)i

= 3\left(-\frac{\sqrt{2}i}{2}+\frac{\sqrt{2}}{2}\right) ÷ -2\sqrt{2}i

= \frac{3\left(1-i\right)}{\sqrt{2}}÷ 2\sqrt{2}i = -3-3i ÷ 4 = -\frac{3}{4}-\frac{3}{4}i

As you can see your solution is the last option.

3 0
3 years ago
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