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Yuri [45]
1 year ago
8

- Lulah is buying beach balls for her beach

Mathematics
1 answer:
Elan Coil [88]1 year ago
5 0

The set of the ordered pairs is a {(1, 6), (2, 12), (3, 18), (4, 24)}.

According to the statement

We have to find that the set of the ordered pairs.

So, For this purpose, we know that the

A function is a set of ordered pairs in which no two different ordered pairs have the same x -coordinate.

From the given information:

The package contains 6 beach balls And

the number of packages x for a total of 1, 2, 3, and 4 packages.

Then

(packages, balls) = (1, 6)

Multiplying by 2, 3, and 4, we find the set of ordered pairs to be ...

{(1, 6), (2, 12), (3, 18), (4, 24)}

So, The set of the ordered pairs is a {(1, 6), (2, 12), (3, 18), (4, 24)}.

Learn more about ordered pairs here

brainly.com/question/1528681

#SPJ9

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Answer:

x = 10

Step-by-step explanation:

I'm not entirely sure what you're asking, however we know that:

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3 years ago
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Let f be defined by the function f(x) = 1/(x^2+9)
riadik2000 [5.3K]

(a)

\displaystyle\int_3^\infty \frac{\mathrm dx}{x^2+9}=\lim_{b\to\infty}\int_{x=3}^{x=b}\frac{\mathrm dx}{x^2+9}

Substitute <em>x</em> = 3 tan(<em>t</em> ) and d<em>x</em> = 3 sec²(<em>t </em>) d<em>t</em> :

\displaystyle\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\frac{3\sec^2(t)}{(3\tan(t))^2+9}\,\mathrm dt=\frac13\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\mathrm dt

=\displaystyle \frac13 \lim_{b\to\infty}\left(\arctan\left(\frac b3\right)-\arctan(1)\right)=\boxed{\dfrac\pi{12}}

(b) The series

\displaystyle \sum_{n=3}^\infty \frac1{n^2+9}

converges by comparison to the convergent <em>p</em>-series,

\displaystyle\sum_{n=3}^\infty\frac1{n^2}

(c) The series

\displaystyle \sum_{n=1}^\infty \frac{(-1)^n (n^2+9)}{e^n}

converges absolutely, since

\displaystyle \sum_{n=1}^\infty \left|\frac{(-1)^n (n^2+9)}{e^n}\right|=\sum_{n=1}^\infty \frac{n^2+9}{e^n} < \sum_{n=1}^\infty \frac{n^2}{e^n} < \sum_{n=1}^\infty \frac1{e^n}=\frac1{e-1}

That is, ∑ (-1)ⁿ (<em>n</em> ² + 9)/<em>e</em>ⁿ converges absolutely because ∑ |(-1)ⁿ (<em>n</em> ² + 9)/<em>e</em>ⁿ| = ∑ (<em>n</em> ² + 9)/<em>e</em>ⁿ in turn converges by comparison to a geometric series.

5 0
3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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BartSMP [9]

Answer:

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Step-by-step explanation:

DE / XY = EF / YZ

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cross-multiply:

10(2x-1) = 14(5)

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20x = 80

x = 4

8 0
3 years ago
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