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Nikitich [7]
3 years ago
11

Your answer must be simplified. −3 < x -10

Mathematics
1 answer:
andrew11 [14]3 years ago
7 0

Answer:

7 < x

Step-by-step explanation:

−3 < x -10

Add 10 to each side

−3+10 < x -10+10

7 < x

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Write the equation of a line with a slope of 5 that passes through the point (3,1)
Brut [27]

Answer:

y-1=5(x-3)

Step-by-step explanation:

y=mx+b where m=slope and b=y-intercept,

y-y1=m(x-x1)

y-1=5(x-3)

5 0
3 years ago
Prove or disprove that (1)/(1-cot x) is the same as (sin x)/(sin x - cos x)
SIZIF [17.4K]
\dfrac{1}{1-\cot x}=\dfrac{\sin x}{\sin x-\cos x}\\\\L_s=\dfrac{1}{1-\dfrac{\cos x}{\sin x}}=\dfrac{1}{\dfrac{\sin x}{\sin x}-\dfrac{\cos x}{\sin x}}=\dfrac{1}{\dfrac{\sin x-\cos x}{\sin x}}=\dfrac{\sin x}{\sin x-\cos x}=R_s

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3 years ago
Explain if you can
Mashutka [201]
Part A: C part B: C. I hope this helps
4 0
3 years ago
Read 2 more answers
A dartboard is divided into 20 sectors. Each sector is worth a point value from 1 to 20 and has shaded regions that double or
Nikitich [7]

The area of each sector is the amount of space on the sector

  • The area of the entire region is 6.89
  • The area of the double region is 0.75
  • The area of the triple region is 0.46

<h3>The area of the entire sector</h3>

The area of a sector is calculated as:

A = (1/2) × r^2θ

For the entire sector, we have:

θ =  π/10

r = 6.625

So, we have:

A = (1/2) × 6.625^2 × π/10

Evaluate the product

A = 6.89

<h3>The area of the double region </h3>

For the double region, we have:

θ =  π/10

r = 6.25

So, we have:

A = Complete sector - (1/2) × r^2θ

A = 6.89 - (1/2) × 6.25^2 × π/10

Evaluate the difference

A = 0.75

<h3>The area of the triple region </h3>

For the triple region, we have:

θ =  π/10

R = 4.125

r = 3.75

So, we have:

A = (1/2) × R^2θ - (1/2) × r^2θ

A = (1/2) × 4.125^2 × π/10 - (1/2) × 3.75^2 × π/10

Evaluate the difference

A = 0.46

Hence, the area of the triple region is 0.46

Read more about sector areas at:

brainly.com/question/16736105

8 0
2 years ago
Can you guys help me??
baherus [9]
Plug the values (1,7) and (3,9) into the functions and see which function is true for both values. In this case, f(x) = x+6 holds true for both values, making it the correct answer.
4 0
3 years ago
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