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d1i1m1o1n [39]
4 years ago
15

The force F of attraction between two bodies varies jointly as the weights of the two bodies and inversely as the square of the

distance between them. Express this fact as a variation using c as a constant. Use M1 and M2 for the weights of the two bodies.
Mathematics
2 answers:
Gekata [30.6K]4 years ago
4 0
We can write this as

F = c  M1 M2 / d^2    where d = distance between the bodies
zubka84 [21]4 years ago
4 0

Answer:

I think the answer is c=F(d^2)/(m_1m_2)

Step-by-step explanation:

REMEMBER: The formula for joint variation is:

c=y/xz OR y=cxz.

Substitute:

F=Km_1m_2/d^2

then change to:

k= constant, they want you to use "c" instead:

c=F(d^2)/(m_1m_2)

Hope this helps!

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In the rolling of two fair dice calculate the following: P(Sum of the two dice is 7) = ______
vesna_86 [32]

Answer:

P(Sum of the two dice is 7) = 6/36

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem, we have that:

A fair dice can have any value between 1 and 6 with equal probability. There are two fair dices, so we have the following possible outcomes.

Possible outcomes

(first rolling, second rolling)

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)

(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)

(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)

(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)

(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)

(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

There are 36 possible outcomes.

Desired outcomes

Sum is 7, so

(1,6), (6,1), (5,2), (2,5), (3,4), (4,3).

There are 6 desired outcomes, that is, the number of outcomes in which the sum of the two dice is 7.

Answer

P(Sum of the two dice is 7) = 6/36

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Answer:

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Step-by-step explanation:

5000m divided by 5m = 1000 trees

Have a nice day!!!!!! :-)

<u>KA</u>

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