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oee [108]
3 years ago
12

Need help ASAP !!!!!!!

Mathematics
1 answer:
Anestetic [448]3 years ago
5 0
First we distribute \frac{1}{5} into n and -\frac{1}{7}.

\frac{1}{5} * n =  \frac{1}{5} n
\frac{1}{5}  *  -\frac{1}{7}  = - \frac{1}{35}

That makes the left side of the equation 

\frac{1}{5} n -  \frac{1}{35} =  \frac{1}{6} n

Now we subtract \frac{1}{5}n from \frac{1}{6} n, which makes \frac{1}{30}

Now the equation is 

-\frac{1}{35} =  -\frac{1}{30n}

Our goal is to isolate n, so we both sides by 30

30* -\frac{1}{35} = - \frac{1}{30}n * 30 

That will make the equation 

- \frac{30}{35} = -n

We multiply -1 on both sides of the equation:

\frac{30}{35} = n

Finally we simplify \frac{30}{35}, which makes \frac{6}{7}

So the answer is n =  \frac{6}{7}
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7 0
3 years ago
The height h(n) of a bouncing ball is an exponential function of the number n of bounces.
Digiron [165]

Answer:

The height of a bouncing ball is defined by h(n) = 6\cdot \left(\frac{4}{6} \right)^{n-1}.

Step-by-step explanation:

According to this statement, we need to derive the expression of the height of a bouncing ball, that is, a function of the number of bounces. The exponential expression of the bouncing ball is of the form:

h = h_{o}\cdot r^{n-1}, n \in \mathbb{N}, 0 < r < 1 (1)

Where:

h_{o} - Height reached by the ball on the first bounce, measured in feet.

r - Decrease rate, no unit.

n - Number of bounces, no unit.

h - Height reached by the ball on the n-th bounce, measured in feet.

The decrease rate is the ratio between heights of two consecutive bounces, that is:

r = \frac{h_{1}}{h_{o}} (2)

Where h_{1} is the height reached by the ball on the second bounce, measured in feet.

If we know that h_{o} = 6\,ft and h_{1} = 4\,ft, then the expression for the height of the bouncing ball is:

h(n) = 6\cdot \left(\frac{4}{6} \right)^{n-1}

The height of a bouncing ball is defined by h(n) = 6\cdot \left(\frac{4}{6} \right)^{n-1}.

5 0
3 years ago
Read 2 more answers
2. Margie Spencer wants to have $100,000 in her savings account in 20 years. If her account pays 6.6% annual
WITCHER [35]

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill & \$100000\\ P=\textit{original amount deposited}\\ r=rate\to 6.6\%\to \frac{6.6}{100}\dotfill &0.066\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{semiannually, thus two} \end{array}\dotfill &2\\ t=years\dotfill &20 \end{cases}

100000=P\left(1+\frac{0.066}{2}\right)^{2\cdot 20}\implies 100000=P(1.033)^{40} \\\\\\ \cfrac{100000}{1.033^{40}}=P\implies 27288.97\approx P

7 0
2 years ago
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