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iVinArrow [24]
3 years ago
7

A multiple choice quiz has two questions , each with five answer choices. Only one choice is correct. Find the probability of an

swering two questions correctly,
. Show work
Mathematics
1 answer:
Leokris [45]3 years ago
4 0

Answer:

1/25 to get both correct

Step-by-step explanation:

So the probability of getting one choice correct is 1/5

Since 5 choices 1 is correct

now we have to get 2 in a row correct so

1/5*1/5=1/25

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A system of equations and its solution are given below.
ratelena [41]

Answer:

B

Step-by-step explanation:

The second equation in system B is only in terms of y, so we need to use elimination to eliminate the x term from the second equation in system A.

To do that, we need to multiply the first equation by 5.

5 (-x − 2y = 7)

-5x − 10y = 35

Add to the second equation.  Notice the x terms cancel out.

(-5x − 10y) + (5x − 6y) = 35 + (-3)

-16y = 32

Combining this new equation with the first equation from system A will get us system B.

-x − 2y = 7

-16y = 32

4 0
3 years ago
Seven pounds of grapes cost $ 10.43 how much would 3 pounds cost
weeeeeb [17]
94. 7 pounds of grapes costs 10.43 dollars. Now, solve for the costs of 3 pounds of grapes. There are different ways to solve this kind of situation. For my end, I will be showing the solution that I think is easier. => 7 pounds = 10.43 dollars. Find the unit rate first => 10.43 dollars / 7 = 1.49 dollars per pounds. Now, solve for the cost of 3 pounds => 1.49 * 3 = 4.47 dollars is the costs of 3 pounds of grapes.
6 0
4 years ago
A teacher would like to estimate the mean number of steps students take during the school day. To do so, she selects a random sa
Helga [31]

Answer:

The answer is "It would decrease, but not necessarily by 8%".

Step-by-step explanation:

They know that width of the confidence level is proportional to a confidence level. As just a result, reducing the confidence level decreases the width of a normal distribution, but not with the amount of variance in the confidence level. As just a result, when a person teaches a 90% standard deviation rather than a 98 percent normal distribution, the width of the duration narrows.

6 0
3 years ago
In order to test whether the average waiting time this year differs from last year, a sample of 25 data were collected this year
irina [24]

Answer:

True

Step-by-step explanation:

Confidence interval for banking service in a given confidence level can be calculated as  M±ME where

  • M is the mean banking service in the sample and
  • ME is the Margin of Error

margin of error (ME) is calculated using the formula

ME=\frac{t*s}{\sqrt{N} } where

  • t is the corresponding statistic in the given confidence level
  • s is the standard deviation of the sample(or of the population if it is known)
  • N is the sample size

t-statistic for 99% confidence level is always bigger than 95% confidence level which makes Margin of Error bigger and thus confidence interval wider.

6 0
4 years ago
Please don't answer if you don't know
andreyandreev [35.5K]
51 + 30 + 69 = 150 total
probability purchased grape flavor = 30/150 = 0.2

answer
A. 0.2
6 0
4 years ago
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