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3 years ago

20 POINTS AND WILL MARK BRAINLIEST

2 answers:

6 0

Dan815 says:

548 5/8 are 7th grade = 5/8*548=#nmber of 7th graders in total 3/8th are 8th graders = 3/8 *548=#of 8th graders in total 4/5 of Total 7th graders = 4/5*5/8*548 7/8 of total 8th graders = 7/8*3/8*548

Happy studying!

pashok25 [27]3 years ago

6 0

Let's find an eighth of 584. Break this down step by step.

584/8= 73

So, eighth equals = 73.

Now find how many seven and eighth-graders there are by multiplying 73 by the desired number.

73*5= 365 (seventh graders)

73*3= 219 (eighth graders)

So, just divide both numbers by the denominator of the fraction used, and then multiply by the numerator for the correct amount of both who participated.

365/ 5= 73

73*4= 292

292 of the seventh graders participated.

219/8= 27.375

Multiply that by the numerator.

27.375*7= 191.625 (8th graders)

The question said about how many participated, so round 191 up to 192.

292 seventh graders and 192 eighth graders participated in field day.

I hope this helps!
~kaikers

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Answer:

a) $P(X$

And we can find this probability using the normal standard table or excel and we got:

$P(z$

b) $P(X>48)=P(\frac{X-\mu}{\sigma}>\frac{48-\mu}{\sigma})=P(Z>\frac{48-46.8}{1.75})=P(z>0.686)$

And we can find this probability using the complement rule, the normal standard table or excel and we got:

$P(z>0.686)=1- P(Z$

c) $P(46.8-1.5*1.75$

And we can find this probability with this difference:

$P(-1.5$

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.

$P(-1.5$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the velocities of a population, and for this case we know the distribution for X is given by:

$X \sim N(46.8,1.75)$

Where $\mu=46.8$ and $\sigma=1.75$

We are interested on this probability

$P(X$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X$

And we can find this probability using the normal standard table or excel and we got:

$P(z$

Part b

$P(X>48)=P(\frac{X-\mu}{\sigma}>\frac{48-\mu}{\sigma})=P(Z>\frac{48-46.8}{1.75})=P(z>0.686)$

And we can find this probability using the complement rule, the normal standard table or excel and we got:

$P(z>0.686)=1- P(Z$

Part c

$P(46.8-1.5*1.75$

And we can find this probability with this difference:

$P(-1.5$

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.

$P(-1.5$

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3 years ago