How to solve this equation? Will give brainiest!!

The following from least to greatest.<br> 64%, 1_5 0.567

weqwewe [10]

Answer:

e

Step-by-step explanation:

e

3 0

3 years ago

Read 2 more answers

Point S is on line segment R T ‾ RT . Given R S = 4 x − 10 , RS=4x−10, S T = 2 x − 10 , ST=2x−10, and R T = 4 x − 4 , RT=4x−4, d

mylen [45]

Question not well presented

Point S is on line segment RT . Given RS = 4x − 10, ST=2x−10, and RT=4x−4, determine the numerical length of RS

Answer:

The numerical length of RS is 22

Step-by-step explanation:

Given that

RS = 4x − 10

ST=2x−10

RT=4x−4

From the question above:

Point S lies on |RT|

So, RT = RS + ST

Substitute values for each in the above equation to solve for x

4x - 4 = 4x - 10 + 2x - 10 --- collect like terms

4x - 4 = 4x + 2x - 10 - 10

4x - 4 = 6x - 20--- collect like terms

6x - 4x = 20 - 4

2x = 16 --- divide through by 2

2x/2 = 16/2

x = 8

Since, RS = 4x − 10

RS = 4*8 - 10

RS = 32 - 10

RS = 22

Hence, the numerical length of RS is calculated as 22

8 0

2 years ago

What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?

Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

Given the equation:

$\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}$

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

$\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}$

- Using the Difference of squares formula ( $a^2-b^2=(a+b)(a-b)$ ) we can simplify the denominator of the right side of the equation:

$\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}$

- Multiply both sides of the equation by $(m+3)(3-m)$ and simplify:

$\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}$

- Multiply both sides by $m-3$ :

$(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)$

- Apply Distributive property and simplify:

$(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0$

- Divide both sides of the equation by -6:

$\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0$

- Factor the equation and solve for "m":

$(m-3)^2=0\\\\m=3$

In order to verify it, you must substitute $m=3$ into the equation and solve it:

$\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}$

<em>NO SOLUTION</em>

7 0

3 years ago

Is number 1 true or false

vekshin1

Answer:

true

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

I needddd helppp pleaseeeeee

UNO [17]

Answer:

has to be letter b because they connect and then separate opposite sides

3 0

2 years ago