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vaieri [72.5K]
3 years ago
8

Given fx) = 10– 2x, find (7). оооо 7 56

Mathematics
1 answer:
damaskus [11]3 years ago
8 0

Answer:

Substitute the value of 7 into the variable x. Then solve the equation.

f(7) = 10 - 2(7)

f(7) = 10 - 14

<h2><em><u>f(7) = -4 is the answer.</u></em></h2>
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2 points) Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One
Stells [14]

y'=(t+y)^2-1

Substitute u=t+y, so that u'=y', and

u'=u^2-1

which is separable as

\dfrac{u'}{u^2-1}=1

Integrate both sides with respect to t. For the integral on the left, first split into partial fractions:

\dfrac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)=1

\displaystyle\int\frac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)\,\mathrm dt=\int\mathrm dt

\dfrac12(\ln|u-1|-\ln|u+1|)=t+C

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\dfrac12\ln\left|\dfrac{u-1}{u+1}\right|=t+C

\ln\left|1-\dfrac2{u+1}\right|=2t+C

1-\dfrac2{u+1}=e^{2t+C}=Ce^{2t}

\dfrac2{u+1}=1-Ce^{2t}

\dfrac{u+1}2=\dfrac1{1-Ce^{2t}}

u=\dfrac2{1-Ce^{2t}}-1

Replace u and solve for y:

t+y=\dfrac2{1-Ce^{2t}}-1

y=\dfrac2{1-Ce^{2t}}-1-t

Now use the given initial condition to solve for C:

y(3)=4\implies4=\dfrac2{1-Ce^6}-1-3\implies C=\dfrac3{4e^6}

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y=\dfrac2{1-\frac34e^{2t-6}}-1-t=\boxed{\dfrac8{4-3e^{2t-6}}-1-t}

3 0
2 years ago
(35 ÷ 5) - 5<br><br> show work!! help
saveliy_v [14]

Answer:

Step-by-step explanation:

(35/5) - 5

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julia-pushkina [17]
Hello There! ^_^

Your question: To ________ a formula or equation for a specified variable means to rearrange it so that the variable appears alone on one side of the equal sign.

Your answer: To solve <span>a formula or equation for a specified variable means to rearrange it so that the variable appears alone on one side of the equal sign.
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The answer is solve to fill up the blank.

Hope this helps!





7 0
3 years ago
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Consider 10 married couples. how many ways can 7 married couples be selected from this group
Novay_Z [31]
10c7
=10!/(7!*(10-7)!)
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3 years ago
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