2 years ago

5)

1 answer:

7 0

Answer:

i think the 2nd one

Step-by-step explanation:

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Olin [163]

$2\cdot x^2+2\cdot x^1+1\cdot x^0=25\\2x^2+2x+1=25\\2x^2+2x-24=0\\x^2+x-12=0\\x^2+4x-3x-12=0\\x(x+4)-3(x+4)=0\\(x-3)(x+4)=0\\x=3 \vee x=-4$

The base can't be negative, therefore $x=3$ .

$3\cdot x^0+3\cdot x^1+4\cdot x^0-4\cdot x^1+0\cdot x^0=0\\3+3x+4-4x=0\\x=7$

$2\cdot x^1+3\cdotx^0=1\cdot 2^3+1\cdot2^2+1\cdot2^1+1\cdot2^0\\2x+1=8+4+2+1\\2x=14\\x=7$

5 0

2 years ago

alexandr1967 [171]

i don’t rly remember surface area i’m sorry i couldn’t help

8 0

3 years ago

dmitriy555 [2]

I think it’s maybe C

8 0

3 years ago

torisob [31]

The answer should be 3/5

4 0

3 years ago

Tpy6a [65]

Tom will get £166
Ben will get £581

4 0

3 years ago