according to the question
3x-1=0
3x=1
x=⅓
so
f(x)=18x³+x-1
f(⅓)=18.(⅓)³+⅓-1
f(⅓)=18.⅓.⅓.⅓+⅓-1
f(⅓)=6.⅑+⅓-1
f(⅓)=⅔+½-1
f(⅓)=0
<h3>therefore</h3><h3> the remainder is 0</h3>
I believe the answer is 3
Here we might have to find p(v intersection w) and for that we use the following formula
p(v U w) = p(v)+p(w)-p(v intersection w)
And it is given that p(v) =01.3 , p(w) = 0.04 and p(v U w ) = 0.14 .
Substituting these values in the formula, we will get
0.14 = 0.13 +0.04 -p(v intersection w)
p(v intersection w) =0.13 +0.04 -0.14 = 0.03
So the required answer of the given question is 0.03 .
