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Aleks [24]
3 years ago
14

Which of these numbers is GREATEST? A) 5.7 × 106 B) 5.7 × 107 C) 5.07 × 106 D) 5.07 × 107

Mathematics
1 answer:
Vaselesa [24]3 years ago
3 0

Answer:

B) 5.7 × 107 = 609.9

Step-by-step explanation:

A) 604.2

B) 609.9

C) 537.42

D) 542.49

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LiRa [457]
I think this is right

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Law of Sines or Law of Cosines....Help!!
iren2701 [21]

Answer:

Law of cosines to find missing measures

c^2= a^2+ b^2 - 2ab*cos(C)

Used because it is a SAS triangle

Step-by-step explanation:

This is known as a side, angle, side, or SAS triangle. We can find the missing measures by using the Law of cosines

c^2= a^2+b^2-2ab*cos(C)

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3 years ago
Four times a number added to 3 times a larger number is 31. Seven subtracted from the larger number is equal to twice the smalle
aev [14]
Let the smaller number be x.
Let the bigger number be y.

\begin{cases} &4x + 3y = 31 \tex{ ----- (1) } \\ &y- 7 = 2x \tex{ ----- (2) } \end{cases}

Rearrange equation (2):
\begin{cases} &4x + 3y = 31 \tex{ ----- (1) } \\ &y = 2x + 7 \tex{ ----- (2) } \end{cases}



Sub (2) into (1):

4x + 3(2x + 7 ) = 31
4x + 6x + 21 = 31
10x + 21 = 31
10x = 10
x = 1

Sub x = 1 into (2):

y = 2x + 7
y = 2(1) + 7
y= 9

Answer: The two numbers are 1 and 9.

5 0
3 years ago
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What percent of 600 is 12 in proportion
MatroZZZ [7]
I am doing most of it on my own. But other people post their answers from the internet as well. Thanks for your imput. 
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3 years ago
#2: Solve the linear system below using the elimination method. Type your
MariettaO [177]

The given linear system is:

\displaystyle \left \{ {{5x+7y=33} \atop {11x+7y=39}} \right.

The question is asking to solve using elimination. When eliminating, you can either eliminate x or y. In this system, y is much easier to eliminate. The y variable in both equations are 7y. To eliminate, one of them has to be negative, so multiply one of the equations by -1.

I will be multiplying the second equation by -1.

\displaystyle (11x + 7y = 39) \times -1 = -11x-7y=-39

Rewrite the system:

\displaystyle \left \{ {{5x+7y=33} \atop {-11x-7y=-39}} \right.

Subtract:

5x+7y=33\\-11x-7y=-39

5x-11x=33-39\\-6x=-6

Lastly, you need to leave the variable x alone. The variable is currently -6x or -6 times x. To remove it, you need to do the opposite of it, which is dividing by -6.

\displaystyle \frac{-6x}{-6} =\frac{-6}{-6}

\displaystyle x=1

Now that you have the value of x, substitute it into one of the equations to find y. I will be substituting it into the first equation.

5x+7y=33 \rightarrow 5(1)+7y=33

Open the parentheses and multiply:

5+7y=33

Move 5 to the other side to leave the variable alone:

5+7y-5=33-5

You will be subtracting since you're "removing" it by doing the opposite of it.

7y=28

Lastly, divide both sides by 7 to leave y alone.

\displaystyle \frac{7y}{7} =\frac{28}{7}

y=4

\displaystyle (x,y) \rightarrow (1, 4)

The answer is (1, 4).

8 0
2 years ago
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