Let x be the distance (in feet) along the road that the car has traveled and h be the distance (in feet) between the car
and the observer.
(a) Before the car passes the observer, we have dh/dt < 0; after it passes, we have dh/dt > 0. So at the instant it passes the observer we have
dh/dt = 0, given that dh/dt varies continuously since the car travels at a constant velocity.
Answer:
34 square units
Step-by-step explanation:
The figure can be considered to be a trapezoid with a rectangle removed.
The area of the trapezoid is ...
A = (1/2)(b1 +b2)h
A = (1/2)(10 +6)(5) = 40
The area of the rectangle is ...
A = LW
A = (3)(2) = 6
Then the area of the shaded portion of the figure is ...
shaded area = trapezoid area - rectangle area
= 40 - 6 = 34 . . . square units
Answer:
No, it isnt a solution
Step-by-step explanation:
Even though it works for one equation, it doesnt work on the other. You have to have the solution work for both equations so that it can be a true solution. Hope this helps you understand!
699,548
655,417
689,414
701,000
Answer: B
Exclamation: a.p.e.x
