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Gelneren [198K]
3 years ago
9

PLSSSSSSS HELP ASAP I IS DEAD

Mathematics
2 answers:
RideAnS [48]3 years ago
8 0

Answer:

The answer is 24.

Step-by-step explanation:

If you multiply 3/4 by 8, you would get 6. Then, subtract 6 from 30, you would get 24. Larry's profit would be only $24.

lions [1.4K]3 years ago
6 0
The answer is 24!!!!!!!!!!!
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What are the missing terms 64, -32, 16, -8, ___, ___?
Daniel [21]

Divide by -2 for all of the numbers

64/-32=-2

-32/ 2= -16

-16/2= -8

-8/-2= 4

4/-2= -2

Answer : 4 ,-2

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3 years ago
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Need help with a math question
ryzh [129]

Answer:

27%

Step-by-step explanation:

take the number of times it is at 2 cars (16) and divide by the number of surveyed times in total (60). multiply by 100 to show answer as a percent

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3 years ago
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What is -12x-5(-8)=40​
ololo11 [35]

Answer: 0

Step-by-step explanation:

4 0
2 years ago
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What is the product in simplest form state any restrictions on the variable x^2+9x+18/x+ times x^2-3x-10/x^2+2x-24?
Ostrovityanka [42]

Answer:

<u>X^4+26X^3-24X^2-100 / X^2</u>

<u>(its a fraction btw)</u>

Step-by-step explanation:

ITS THE EQUATION SIMPLIFIED :)

x2+9x+ 18 x x2−3x− 10 x2 +2x−24

= x5+26x4−24x3−10x  x3

↓↓↓↓looks like this kinda ↓↓↓↓

x^4+26x^3−24x^2−10

---------------------------------

            x^2

6 0
3 years ago
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Use the Chain Rule to find the indicated partial derivatives. z = x^4 + xy^3, x = uv^4 + w^3, y = u + ve^w Find : ∂z/∂u , ∂z/∂v
k0ka [10]

I'll use subscript notation for brevity, i.e. \frac{\partial f}{\partial x}=f_x.

By the chain rule,

z_u=z_xx_u+z_yy_u

z_v=z_xx_v+z_yy_v

z_w=z_xx_w+z_yy_w

We have

z=x^4+xy^3\implies\begin{cases}z_x=4x^3+y^3\\z_y=3xy^2\end{cases}

and

\begin{cases}x=uv^4+w^3\\y=u+ve^w\end{cases}\implies\begin{cases}x_u=v^4\\x_v=4uv^3\\x_w=3w^2\\y_u=1\\y_v=e^w\\y_w=ve^w\end{cases}

When u=1,v=1,w=0, we have

\begin{cases}x(1,1,0)=1\\y(1,1,0)=2\end{cases}\implies\begin{cases}z_x(1,2)=12\\z_y(1,2)=12\end{cases}

and the partial derivatives take on values of

\begin{cases}x_u(1,1,0)=1\\x_v(1,1,0)=4\\x_w(1,1,0)=0\\y_u(1,1,0)=1\\y_v(1,1,0)=1\\y_w(1,1,0)=1\end{cases}

So we end up with

\boxed{\begin{cases}z_u(1,1,0)=24\\z_v(1,1,0)=60\\z_w(1,1,0)=12\end{cases}}

3 0
3 years ago
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