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Elden [556K]
3 years ago
6

Emma has 460 ballet stickers in her collection. Each month she adds 28 more stickers to her collection.

Mathematics
1 answer:
MArishka [77]3 years ago
3 0
I believe you would multiply 28 by 7, then add that to 460
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The answer to this question here in the photo cause I don’t know this
Lady bird [3.3K]

Answer:

19.

Step-by-step explanation:

PEMDAS.
3^2=9
5 x 2 + 9
10 + 9 = 19

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2 years ago
Wo runners are saving money to attend a marathon. The first runner has $112 in savings, received a $45 gift from a friend, and w
SpyIntel [72]

Answer:

I believe the last answer is correct

Step-by-step explanation:

Both runners are gaining money

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2 years ago
3. write an equation of the circle whose center is (-5,2) and whose radius length is 4 express your answer in standard form. I N
marin [14]
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3 years ago
Expand the expression (5x + 3)2, and write the result in standard form.
Nikolay [14]

Expand

2 × 5x + 2 × 3

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10x + 2 × 3

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3 0
3 years ago
The distances male long jumpers for State College jump are approximately normal with a mean of 263 inches and a standard deviati
Effectus [21]

Answer:

His jump was of 272.45 inches

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 263, \sigma = 14

75th percentile

X when Z has a pvalue of 0.75. So X when Z = 0.675

Z = \frac{X - \mu}{\sigma}

0.675 = \frac{X - 263}{14}

X - 263 = 14*0.675

X = 272.45

His jump was of 272.45 inches

7 0
3 years ago
Read 2 more answers
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