To find the original price, you could use a variable to represent the original price in this equation;
Let p represent the original price
.70 × p=11.20
to solve this, we'd isolate the variable (p)
p=11.20 ÷.70
p=16
The original price was $16
Answer:
$5.50
Step-by-step explanation:
2.50divided by 10= .25
.25 times 22= 5.50
Answer:
88
Step-by-step explanation:
Write the expression for the sum in the relation you want.
Sn = u1(r^n -1)/(r -1) = 2.1(1.06^n -1)/(1.06 -1)
Sn = (2.1/0.06)(1.06^n -1) = 35(1.06^n -1)
The relation we want is ...
Sn > 5543
35(1.06^n -1) > 5543 . . . . substitute for Sn
1.06^n -1 > 5543/35 . . . . divide by 35
1.06^n > 5578/35 . . . . . . add 1
n·log(1.06) > log(5578/35) . . . take the log
n > 87.03 . . . . . . . . . . . . . . divide by the coefficient of n
The least value of n such that Sn > 5543 is 88.
Neither is greater.
1 quart = 4 cups
2 quarts = 8 cups
3 quarts = 12 cups
So they're equal.