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Marina CMI [18]

3 years ago

11

Suppose you have the following recursion formula a1 = 1, a2 = 2, and an = a(n - 1)+ a(n - 2)for integers n ≥ 3. How would you de

termine the next 3 terms?

1 answer:

julia-pushkina [17]3 years ago

8 0

A3=3
a4=5
a5=8

This sequence has properties similar to those of the Fibonacci sequence.

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Which numbers have the same absolute value? Choose all that apply. ASAP

Vitek1552 [10]

I'm not sure which numbers you are referring to, but 3 has the same absolute value as -3, and 7 has the same absolute value as -7, just for an example.

3 0

3 years ago

Carla is a drummer in the school band. By the end of the year, she had played in 85% of the 20 concerts the band played. How man

Margarita [4]

Answer:

29

Step-by-step explanation:

3 0

2 years ago

Someone help please!!!!

LUCKY_DIMON [66]

Answer:

x = -2

TU = 4

UB = 2

Step-by-step explanation:

you can add x^2 with 4x+10 and equate it to 6:

x^2 + 4x + 10 = 6

x^2 + 4x + 4

then u can use the roots formula : x = (-b ± √ (b2 - 4ac) )/2a

so it'll be x = {-4±[√16 - 4(4)]}/2

x= -2

then u can substitute it and find TU and UB

TU= (-2)^2 = 4

UB= 4(-2)+10 = 2

5 0

2 years ago

the vertices of PQR are P(-5,1), Q(-4,6), and R(-2,3), graph P"Q"R" after a composition of the transformations in the order they

horsena [70]

SOLUTION

We are told to translate; (x, y) to (x -8, y). This means we have to add - 8 to each value of x in P(-5,1), Q(-4,6), and R(-2,3).

In P(-5,1), x = -5 and y = 1

In Q(-4,6), x = -4 and y = 6 and

In R(-2,3), x = -2 and y = 3

$\begin{gathered} P(-5,\text{ 1) translates to (-5 -8, 1) }\rightarrow P^i(-13,\text{ 1)} \\ Q(-4,\text{ 6) translates to (-4 -8, 6) }\rightarrow Q^i(-12,\text{ 6)} \\ R(-2,\text{ 3) translates to (-2 -8, 3) }\rightarrow R^i(-10,\text{ 3)} \end{gathered}$

For the dilation centered at the origin k =2, simply multiply the value of k, which is 2 into the translations.

$\begin{gathered} At\text{ K = 2, }P^i(-13,\text{ 1) }\rightarrow\text{ }2(-13,\text{ 1) }\rightarrow\text{ }P^{ii}(-26,\text{ 2)} \\ Q^i(-12,\text{ 6) }\rightarrow\text{ }2(-12,\text{ 6) }\rightarrow\text{ Q}^{ii}(-24,\text{ 12)} \\ R^i(-10,\text{ 3) }\rightarrow\text{ }2(-10,\text{ 3) }\rightarrow\text{ R}^{ii}(-20,\text{ 6)} \end{gathered}$

5 0

1 year ago

What is the probability of getting the same number of heads and tails?<br>1/8<br>1/4<br>3/8<br>3/4

victus00 [196]

The probability of getting the same number of heads and tails is3/8

4 0

3 years ago