Answer:
- <u>59.0891 g (rounded to 4 decimal places)</u>
Explanation:
<em>Half-life time</em> of a radioactive substance is the time for half of the substance to decay.
Thus, the amount of the radioactive substance that remains after a number n of half-lives is given by:
Where:
- A is the amount that remains of the substance after n half-lives have elapses, and
- A₀ is the starting amount of the substance.
In this problem, you have that the half-live for your sample (polonium-210) is 138 days and the number of days elapsed is 330 days. Thus, the number of half-lives elapsed is:
- 330 days / 138 days = 2.3913
Therefore, the amount of polonium-210 that will be left in 330 days is:
Answer:
-12
1
9
13
Step-by-step explanation:
its just the numbers in front of the variables
Answer:
$64188.26
Step-by-step explanation:
→ Calculate the increase in decimal multiplier
( 100 + 3 ) ÷ 100 = 1.03
→ Multiply this by the salary raised to the power of 16
40000 × ( 1.03 )¹⁶
→ Solve
$64188.26
Answer:
The equation of a line is typically written as y=mx+b where m is the slope and b is the y-intercept.
Step-by-step explanation: