<span>The simplest method to do this is with the vector dot
product. Let the vector A = <9i + 5j> with magnitude √106 be the base
diagonal, and B = <5j + 3k> be the diagonal vector on the side, with
magnitude √34. Then cos θ = (A dot B) divided by the product of the magnitudes.
A dot B =30, so
cos θ = 30 / √(34 x 106)</span>
<span> = 0.4997 ==></span>
<span> θ = 49.19° is the
answer</span>
20,27,34
The common difference is 7
The answer is A, first the question said parallel so it should have same gradient and the gradient of the equation is 2 So eliminate D and bring (3,1) in each of the last three equation, and you will find just A conformed
5a+b = 5(6)+3 =3
10-r+5 = 10-(9)+5 =6
Answer:
I think the option B suits the most
Step-by-step explanation:
