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vesna_86 [32]
3 years ago
6

c) The GCF and LCM of two numbers are 2 and 70 respectively. If one of the numbers is 10, find the other number? [3m] solution:

of too numbers​
Mathematics
1 answer:
Mice21 [21]3 years ago
8 0

Their LCM is

70

hope it helps you.

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What is the area of a triangle with vertices at (-2, -1), (4, -1), (6,5)?
Rina8888 [55]
18 square units should be the right answer
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If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w
MatroZZZ [7]

Let x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11} be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.

2. If the mean weight of the 7 other players is 202 lb, then

\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.

3. From the previous statements you have that

x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.

Add these two equalities and then divide by 11:

x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.

Answer: the mean weight of the 11-person team is 208\dfrac{10}{11}\ lb.

4 0
3 years ago
Angles P and Q are supplementary angles. If m
RSB [31]

Supplimentary angles add upto 180 degrees.

Given that angle P is three times angle Q-4 then ;

Let angle P be 3(x-4) = 3x -12

Let angle Q be x

Applying the rule of supplimentary angles;

3x-12+x=1804x-12=1804x=180+124x=192

Divide both sides by 4 to get value of x in degrees

x=\frac{192}{4}=48

x= 48 degrees

Angle Q = 48 degrees

Angle P = 3x-12 = (3*48)-12 = 132 degrees

7 0
1 year ago
What is the surface area of the rectangular pyramid
posledela

Answer:

<h2>41.74 m²</h2>

Step-by-step explanation:

We have:

rectangle 4.8 m × 3.8 m

two triangles with base b = 4.8 m and height h = 2.6 m

two triangle with base b = 3.8 m and height h = 2.9 m.

The formula of an area of a rectangle l × w:

A = lw

Substitute:

A_1 = (4.8)(3.8) = 18.24\ m^2

The formula of an area of a triangle:

A=\dfrac{bh}{2}

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The Surface Area:

S.A.=A_1+2A_2+2A_3\\\\S.A.=18.24+2(6.24)+2(5.51)=41.74\ m^2

3 0
3 years ago
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