P = ab^2
q = a^3 b
p = a * b * b
q = a*a*a * b
Pairing the duplicates we have LCM = a*a*a*b*b = a^3 b^2 answer
Answer:
The measure of ∠EFG is 52°
Step-by-step explanation:
Given line m is parallel to line p. m∠HEF = 39º and m∠IGF = 13º.we have to find m∠EFG.
In ΔJFG,
By angle sum property of triangle, which states that sum of all angles of triangle is 180°
m∠FJG+m∠JGF+m∠JFG=180°
⇒ 39°+13°+m∠JFG=180°
⇒ m∠JFG=180°-39°-13°=128°
As JFE is a straight line ∴ ∠JFG and ∠EFG forms linear pair
⇒ m∠JFG+m∠EFG=180°
⇒ 128°+m∠EFG=180°
⇒ m∠EFG=52°
The measure of ∠EFG is 52°
Lines AB and AC are equal so you set up an equation like so...
4x + 1 = 2x + 23
Subtract 1 from both sides.
4x = 2x + 22
Subtract 2x from both sides.
2x = 22
Divide.
x = 11
Now you need to plug in 11 into 3x - 8.
3(11) - 8
= 33 - 8
= 25
So BC is 25.
I hope this helps love! :)
Answer:
x = 17
Step-by-step explanation:
corresponding interior angles are supplementary, meaning they have to add up to 180 degrees so
6x + 8 + 4x + 2 = 180° then combine like terms ( 6x and 4x, 8 and 2 )
10x + 10 = 180 subtract 10 from both sides
-10 -10
10x = 170 divide each side by 10
/10 /10
x = 17
Answer:
A, 12:47
Step-by-step explanation:
