Given: <span>2x-y-3=0.
find </span>equation for the line perpendicular to the given line that goes through the given point:<span>
(2;-1)koord of direction vector (i`m not know how it is called at you, because i'm from russia)</span><span>
=> (x-0)/2=(y-4)/-1 (</span>canonical <span>equation)
=>x+2y-8=0(general </span><span>equation)
</span>
<span>further:
{x+2y-8=0
{2x-y-3 =0 => y=13/5 x=14/5
(14/5; 13/5) - koord point on line
</span>|dist|=sqrt( (14/5-0)^2 + (13/5-4)^2 ) = sqtr(7.72) = 2.78
Удачи!
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</span>
<h2>
Answer:<em>
</em><em><u>
w =(-40-√4320)/-34=(20+6√ 30 )/17= 3.110
</u></em></h2><h2><em><u>
w =(-40+√4320)/-34=(20-6√ 30 )/17= -0.757</u></em></h2>
Step-by-step explanation: The prime factorization of 4320 is
2•2•2•2•2•3•3•3•5
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 4320 = √ 2•2•2•2•2•3•3•3•5 =2•2•3•√ 30 =
± 12 • √ 30
√ 30 , rounded to 4 decimal digits, is 5.4772
So now we are looking at:
w = ( -40 ± 12 • 5.477 ) / -34
Two real solutions:
w =(-40+√4320)/-34=(20-6√ 30 )/17= -0.757
or:
w =(-40-√4320)/-34=(20+6√ 30 )/17= 3.110
MY HEAD HURTS!
Answer:
−7k^4−11k^2+6
Step-by-step explanation:
−4k^4+14+3k^2−3k^4−14k^2−8
(−4k^4+−3k^4)+(3k^2+−14k^2)+(14+−8)
−7k^4−11k^2+6
...
Answer:
The answer to your question is the second choice (y ≥ 1/3x - 1)
Step-by-step explanation:
Process
1.- Find two points of the graph
A (0, -1)
B (3, 0)
2.- Find the slope
m = (0 + 1)/(3 - 0)
m = 1/3
3.- Find the equation of the line
y - y1 = m(x - x1)
y + 1 = 1/3(x - 0)
y + 1 = 1/3x
y = 1/3x - 1
4.- Find the equation of the inequality
We need the upper part of the line so the inequality must be
y ≥ 1/3x - 1
Answer: The correct answer is the last one shown in the picture
Step-by-step explanation:
It’s the correct answer because when you subtract the two given equations with like terms you will get (- 25/8x + 63/10) —> when you simplify this you get (-3 1/8x + 6 3/10)