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Fofino [41]
3 years ago
15

2. Perform the following multiplication: (+5)(-2)(+7)(-4)(-1)

Mathematics
2 answers:
amid [387]3 years ago
8 0
The answer would be NEGATIVE 280
padilas [110]3 years ago
3 0

Answer:5

Step-by-step explanation:

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Which expression is equivalent to<br> (fg) (5)? <br> F(5)* g(5) <br> F(5)+g(5)<br> 5f(5)<br> 5g(5)
Alexxandr [17]

Answer:

they F (5) g (5)

Step-by-step explanation:

(fg)=(f.g)

and then this is the first doing (fg)(X)= f(x) [g(x)]

x=5

f(5).g(X)

and they final result is

they top of answer

happy answering

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The answer is to complicated for my small brain so ask someone else

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A certain virus infects one in every 200 people. a test used to detect the virus in a person is positive 70​% of the time when t
V125BC [204]

We're told that

P(A)=\dfrac1{200}=0.005\implies P(A^C)=0.995

P(B\mid A)=0.7

P(B\mid A^C)=0.05

a. We want to find P(A\mid B). By definition of conditional probability,

P(A\mid B)=\dfrac{P(A\cap B)}{P(B)}

By the law of total probability,

P(B)=P(B\cap A)+P(B\cap A^C)=P(B\mid A)P(A)+P(B\mid A^C)P(A^C)

Then

P(A\mid B)=\dfrac{P(B\mid A)P(A)}{P(B\mid A)P(A)+P(B\mid A^C)P(A^C)}\approx0.0657

(the first equality is Bayes' theorem)

b. We want to find P(A^C\mid B^C).

P(A^C\mid B^C)=\dfrac{P(A^C\cap B^C)}{P(B^C)}=\dfrac{P(B^C\mid A^C)P(A^C)}{1-P(B)}\approx0.9984

since P(B^C\mid A^C)=1-P(B\mid A^C).

4 0
3 years ago
What is a decimal that is equivalent to 5/10?<br> ? Enter the answer in the box.
sveta [45]

Answer:

0.5

Step-by-step explanation:

It is what it is

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3 years ago
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