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expeople1 [14]
3 years ago
15

If 3(y+13) = 33 find the value of 1/4y

Mathematics
1 answer:
marshall27 [118]3 years ago
3 0

Answer:

Step-by-step explanation:

3y + 39 = 33

3y = -6

y = -2

1/4(-2)= -2/4 = -1/2

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a recipe for a batch of cookie calls for 1/2 cup of sugar and 1/4 cup of brown sugar.how much sugar will you need to use for one
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What is the rule of -3,18,-108,—,—,—
lisabon 2012 [21]

Hi! ❄

   - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

The rule for this sequence is 'multiply by -6'.

Verification ↓

-3*(-6)\stackrel\checkmark{=}18

18*(-6)\stackrel\checkmark{=}-108

So the rule for the sequence is 'multiply by -6'

And the Common ratio is -6.

Hope that made sense !!

  - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

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3 years ago
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Answer:

The given fraction \frac{x^3-x^2}{x^3} reduces to  \frac{x-1}{x}

Step-by-step explanation:

Consider the given fraction \frac{x^3-x^2}{x^3}

We have to reduce the fraction to the lowest terms.

Consider numerator x^3-x^2

We can take x² common from both the term,

Thus, numerator can be written as x^2(x-1)

Given expression can be rewritten as ,

\frac{x^3-x^2}{x^3}=\frac{x^2(x-1)}{x^3}

We can now cancel x^2 from both numerator and denominator,

\Rightarrow \frac{x^2(x-1)}{x^3}=\frac{x^2(x-1)}{x^2 \cdot x}

\Rightarrow \frac{(x-1)}{x^2 \cdot x}=\frac{x-1}{x}

Thus, the given fraction \frac{x^3-x^2}{x^3} reduces to  \frac{x-1}{x}

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