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xxTIMURxx [149]

3 years ago

8

for f(x)=1/x-5 and g(x)=x^2+2 find the expression for g(x) and substitute the value of g(x) into the function in place of x to f

ind the value of f(g(x))

1 answer:

IRISSAK [1]3 years ago

5 0

Answer:

f(x) = (1/x) - 5

g(x) = x^2 + 2

=> f[g(x)] = [1/(x^2 +2)] - 5

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The following data represent the pulse rates? (beats per? minute) of nine students enrolled in a statistics course. Treat the ni

charle [14.2K]

Answer:

(a)77.4bpm

(b)Mean of Sample 1 = 70.3 beats per minute.

Mean pulse of sample 2 = 70 beats per minute.

(c)

The mean pulse rate of sample 1 underestimates the population mean.
The mean pulse rate of sample 2 underestimates the population mean.

Step-by-step explanation:

(a)Population mean pulse.

The pulse of the nine students which represent the population are:

Perpectual Bempah 64
Megan Brooks 77
Jeff Honeycutt 89
Clarice Jefferson 69
Crystal Kurtenbach 89
Janette Lantka 65
Kevin McCarthy 88
Tammy Ohm 69
Kathy Wojdya 87

$\text{Population Mean} =\dfrac{64+77+89+69+89+65+88+69+87}{9} \\=\dfrac{697}{9} \\\\=77.44$

The population mean pulse is approximately 77.4 beats per minute.

(b)Sample 1: {Janette,Clarice,Megan}

Janette: 65bpm
Clarice: 69bpm
Megan: 77bpm

Mean of Sample 1

$\text{Sample 1 Mean} =\dfrac{65+69+77}{3} \\=\dfrac{211}{3} \\\\=70.3$

Sample 2: {Janette,Clarice,Megan}

Perpetual: 64bpm
Clarice: 69bpm
Megan: 77bpm

Mean of Sample 2

$\text{Sample 2 Mean} =\dfrac{64+69+77}{3} \\=\dfrac{210}{3} \\\\=70$

The mean pulse of sample 1 is approximately 70.3 beats per minute.

The mean pulse of sample 2 is approximately 70 beats per minute.

(c)

The mean pulse rate of sample 1 underestimates the population mean.
The mean pulse rate of sample 2 underestimates the population mean.

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