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Pani-rosa [81]
3 years ago
15

If the baker’s percentage for raisins in a raisin bread formula is 8% and the baker’s percentage for flour is 100%, what amount

of raisins are needed if 14 pounds of flour are used?
Mathematics
1 answer:
svet-max [94.6K]3 years ago
3 0

Answer: 1.12 pounds.


Step-by-step explanation:

1. You have the following information given in the problem above:

-The baker’s percentage for raisins in a raisin bread formula is 8%.

-The baker’s percentage for flour is 100%

2. Therefore, the amount of raisins that are needed if 14 pounds of flour are used is:

\frac{(14)(8)}{100}=1.12 pounds


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. In Habib High School 275 of 300 students received a grade of A, while in Public Hall 120 out of 150 students received a grade
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George believes the Art Club students at his school have an unfair advantage in being assigned to the art class they request. He
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Answer:

  class assignment seems to discriminate against Art Club members

Step-by-step explanation:

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  P(got class | art club) = P(got class & art club)/P(art club)

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  P(got class | not club) = P(got class & not club)/P(not club)

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It looks like George's theory may be incorrect, as a significantly greater percentage of non-club students got their requested class than did club students. The class assignment process and art club membership are not independent, suggesting an unfair disadvantage for club students.

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3 years ago
A recent article in the paper claims that government ethics are at an all-time low. Reporting on a recent sample,
Vitek1552 [10]

Answer:

Probability that more than eight but fewer than 12 of the 20 constituents sampled believe  their representative possesses low ethical standards is 0.417890.

Step-by-step explanation:

We are given that the paper claims that 43% of all constituents believe their representative possesses low ethical standards.

Suppose 20 of a representative's constituents are randomly and independently sampled.

The above situation can be represented through binomial distribution;

P(X=r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,.....

where, n = number of trials (samples) taken = 20 constituents

            r = number of success = more than eight but fewer than 12

            p = probability of success which in our question is probability that

                  all constituents believe their representative possesses low

                  ethical standards, i.e; p = 43%

Let X = <u><em>Number of constituents who believe their representative possesses low ethical standards</em></u>

So, X ~ Binom(n = 20 , p = 0.43)

Now, Probability that more than eight but fewer than 12 of the 20 constituents sampled believe  their representative possesses low ethical standards is given by = P(8 < X < 12)

P(8 < X < 12)  =  P(X = 9) + P(X = 10) + P(X = 11)

= \binom{20}{9} \times 0.43^{9} \times (1-0.43)^{20-9}+ \binom{20}{10} \times 0.43^{10} \times (1-0.43)^{20-10}+\binom{20}{11} \times 0.43^{11} \times (1-0.43)^{20-11}

= 167960 \times 0.43^{9} \times 0.57^{11}+ 184756 \times 0.43^{10} \times 0.57^{10}+167960 \times 0.43^{11} \times 0.57^{9}

= <u>0.417890</u>

<u></u>

Hence, the required probability is 0.417890.

7 0
3 years ago
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