- ➣ Circle:- A two-dimensional geometric figure, a line, consisting of the set of all those points in a plane that are equally distant from a given point (center).
- ➣ Circumference:- The line that bounds a circle or other two-dimensional figure
★ also circumference of a circle is also known as it's perimeter
- ➣To find circumference of circle when use formula
- ➢ r = radius (25inch.)
- ➢ value of π is 3.14
★ Hence circumference of circle=157inch
Hope it helps !
Answer: Yes it is.
Step-by-step explanation: So we are already told that segment AC is congruent to segment DC. They both have a right angle, as indicated by the angle symbol, and they share side-length BC.
According to the Hypotenuse-Leg Theorem, two right triangles that have a congruent hypotenuse and a corresponding, congruent leg are congruent triangles. AC and DC are hypotenuses and they are congruent. And BC, the shared side, is a corresponding congruent leg. And since they are both right triangles, we then know that the HL Theorem applies.
3 | x+12 |=6
Start by distributing 3 to both x and 12
You get 3x+36=6
Subtract 36 from both sides
You then get 3x=-30
Divide 3 from both sides getting
x= -10
Answer:
A
Step-by-step explanation:
first option, as the decrease percentage is applicated on a greater number than the original
e.g.
A
a= 10
B
10 + 50% = 15
15 - 50% = 7,5
A will be greater then B by 25%
Answer:
<h2><DEF = 40</h2><h2><EBF = <EDF = 56</h2><h2><DCF = <DEF =40</h2><h2><CAB = 84</h2>
Step-by-step explanation:
In triangle DEF, we have:
<u>Given</u>:
<EDF=56
<EFD=84
So, <DEF =180 - 56 - 84 =40 (sum of triangle angles is 180)
____________
DE is a midsegment of triangle ACB
( since CD=DA(given)=>D is midpoint of [CD]
and BE = EA => E midpoint of [BA] )
According to midsegment Theorem,
(DE) // (CB) "//"means parallel
and DE = CB/2 = FB =CF
___________
DEBF is a parm /parallelogram.
<u>Proof</u>: (DE) // (FB) ( (DE) // (CB))
AND DE = FB
Then, <EBF = <EDF = 56
___________
DEFC is parm.
<u>Proof</u>: (DE) // (CF) ((DE) // (CB))
And DE = CF
Therefore, <DCF = <DEF =40
___________
In triangle ACB, we have:
<CAB =180 - <ACB - <ABC =180 - 40 - 56 =84(sum of triangle angles is 180)
