Answer:
a rhombus that is the answer
Answer:
(a) 0.932
(b) 0.0653
(c) 0.032
(d) 0.316
(e) 0.251
Step-by-step explanation:
From the table with mean parameter μ = 5, we can compute the following cumulative and density probability
(a) 
(cumulative)
(b) P(X = 8) = 0.0653 (density)
(c) 
(cumulative)
(d) 
(cumulative)
(e) 
Answer:
y = 0
Step-by-step explanation:
It is always a good idea to look at the question and make some observations about it. Here, you might observe ...
- all of the bases are powers of 3: 243 = 3^5; 9 = 3^2
- y is a factor of every exponent
The latter observation is important, because it means that when y=0, every exponential expression has a value of 1. Hence y = 0 is a solution.
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To solve the equation, you can write it in terms of powers of 3.
(3^5)^(-y) = (3^-5)^(3y)·(3^2)^(-2y)
3^(-5y) = 3^(-15y)·3^(-4y)
3^(-5y) = 3^(-19y)
-5y = -19y . . . . . . . . equating exponents; equivalent to taking log base 3
14y = 0 . . . . . . . . . . add 19y
y = 0 . . . . . . . . . . . one solution
______
The rules of exponents we used are ...
(a^b)(a^c) = a^(b+c)
(a^b)^c = a^(bc)
1/a^b = a^-b
