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3 years ago

Please help and explain with these 2 math questions!!!!!!

Mathematics

1 answer:

Volgvan3 years ago

6 0

1) -10x+y=4

Now, you should substitute x in every situation.

* x=-2 => -10*(-2)+y=4... 20+y=4... y=-16

* x=-1 =>-10*(-1)+y=4... 10+y=4... y=-6

*x=0 => -10*0+y=4... y=4

* x=1 => -10*1+y=4... -10+y=4... y=14

* x=2 => -10*2+y=4... -20+y=4... y=24

2) -5x-1=y

For example: x=0

-5*0-1=-1

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I will give you brainliest, if you provide an accurate explanation.

Molodets [167]

Answer:

sqrt(i) =0.707106781 + 0.707106781 i

Most of the numbers we know, and work with, are Real Numbers. The Real Number System includes counting numbers, fractions, terminating decimals, positive numbers, negative numbers, zero, repeating decimals, never ending and non-repeating decimals, numbers that are expressed as radicals, and even pi (π).

The natural numbers are the set of counting numbers

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The addition of two natural numbers creates another natural number.

The multiplication of two natural numbers creates another natural number.

closed under addition and multiplication.

BUT ...

The subtraction of two natural numbers does NOT necessarily create another natural number

The division of two natural numbers does NOT necessarily create another natural number

The whole numbers are the set of counting numbers (natural numbers) along with zero

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• The set of whole numbers is "closed" under addition and multiplication.

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• The integers are the set of all of the natural numbers,

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but NOT under division

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Irrational Numbers:

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8 0

3 years ago

Read 2 more answers

What is 3 to the sixth power

Anarel [89]

= 3^6

=3*3*3*3*3*3

=729

7 0

3 years ago

Read 2 more answers

Remember to show work and explain. Use the math font.

MrMuchimi

Answer:

$\large\boxed{1.\ f^{-1}(x)=4\log(x\sqrt[4]2)}\\\\\boxed{2.\ f^{-1}(x)=\log(x^5+5)}\\\\\boxed{3.\ f^{-1}(x)=\sqrt{4^{x-1}}}$

Step-by-step explanation:

$\log_ab=c\iff a^c=b\\\\n\log_ab=\log_ab^n\\\\a^{\log_ab}=b\\\\\log_aa^n=n\\\\\log_{10}a=\log a\\=============================$

$1.\\y=\left(\dfrac{5^x}{2}\right)^\frac{1}{4}\\\\\text{Exchange x and y. Solve for y:}\\\\\left(\dfrac{5^y}{2}\right)^\frac{1}{4}=x\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\dfrac{(5^y)^\frac{1}{4}}{2^\frac{1}{4}}=x\qquad\text{multiply both sides by }\ 2^\frac{1}{4}\\\\\left(5^y\right)^\frac{1}{4}=2^\frac{1}{4}x\qquad\text{use}\ (a^n)^m=a^{nm}\\\\5^{\frac{1}{4}y}=2^\frac{1}{4}x\qquad\log_5\ \text{of both sides}$

$\log_55^{\frac{1}{4}y}=\log_5\left(2^\frac{1}{4}x\right)\qquad\text{use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\\dfrac{1}{4}y=\log(x\sqrt[4]2)\qquad\text{multiply both sides by 4}\\\\y=4\log(x\sqrt[4]2)$

$--------------------------\\2.\\y=(10^x-5)^\frac{1}{5}\\\\\text{Exchange x and y. Solve for y:}\\\\(10^y-5)^\frac{1}{5}=x\qquad\text{5 power of both sides}\\\\\bigg[(10^y-5)^\frac{1}{5}\bigg]^5=x^5\qquad\text{use}\ (a^n)^m=a^{nm}\\\\(10^y-5)^{\frac{1}{5}\cdot5}=x^5\\\\10^y-5=x^5\qquad\text{add 5 to both sides}\\\\10^y=x^5+5\qquad\log\ \text{of both sides}\\\\\log10^y=\log(x^5+5)\Rightarrow y=\log(x^5+5)$

$--------------------------\\3.\\y=\log_4(4x^2)\\\\\text{Exchange x and y. Solve for y:}\\\\\log_4(4y^2)=x\Rightarrow4^{\log_4(4y^2)}=4^x\\\\4y^2=4^x\qquad\text{divide both sides by 4}\\\\y^2=\dfrac{4^x}{4}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\y^2=4^{x-1}\Rightarrow y=\sqrt{4^{x-1}}$

6 0

3 years ago

A sweater is on sale for 75% of the original price of $44. Calculate the sale price.

Step2247 [10]

Answer:

$11

Step-by-step explanation:

44(0.75)=33

44-33=11

4 0

3 years ago

Read 2 more answers

In which quadrant does θ lie if the following statements are true: cos⁡θ>0 and sin⁡θ>0

Papessa [141]

Answer:

First quadrant

Step-by-step explanation:

cosθ > 0 in first/ fourth quadrants

sinθ > 0 in the first/ second quadrants

sinθ and cosθ are both > 0 in the first quadrant

Then θ lies in the first quadrant

6 0

3 years ago