The correct answer is 3/13. Divided both by 5.
15/65
3/13
<span>, y+2 = (x^2/2) - 2sin(y)
so we are taking the derivative y in respect to x so we have
dy/dx use chain rule on y
so y' = 2x/2 - 2cos(y)*y'
</span><span>Now rearrange it to solve for y'
y' = 2x/2 - 2cos(y)*y'
0 = x - 2cos(y)y' - y'
- x = 2cos(y)y' - y'
-x = y'(2cos(y) - 1)
-x/(2cos(y) - 1) = y'
</span><span>we know when f(2) = 0 so thus y = 0
so when
f'(2) = -2/(2cos(0)-1)
</span><span>2/2 = 1
</span><span>f'(2) = -2/(2cos(0)-1)
cos(0) = 1
thus
f'(2) = -2/(2(1)-1)
= -2/-1
= 2
f'(2) = 2
</span>
Answer:
Cosec <F = 73/55
Step-by-step explanation:
In ΔEFG, the measure of ∠G=90°, GF = 48, EG = 55, and FE = 73. What ratio represents the cosecant of ∠F?
First you must know that;
Cosecant <F = 1/sin<F
Given
∠G=90°, GF = 48, EG = 55, and FE = 73.
ED ,= hyp = 73
EG = opp = 55*side facing <F
Using DOH CAH TOA
Sin theta = opp/hyp
Sin <F= 55/73
Reciprocate both sides
1/sinF = 73/55
Cosec <F = 73/55
