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Orlov [11]
3 years ago
13

Find the slope of the line will mark as brain

Mathematics
1 answer:
vodka [1.7K]3 years ago
7 0

Answer negative 9 is the answer

Step-by-step explanation:

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Bearing a to b is 280 what is bearing b to A
jeka94

Answer:

please see photo attached for detailed analysis.

5 0
2 years ago
Solve the equation. Write your answer as an integer or simplified fraction.
saw5 [17]

<u>Corrected question :</u>

Solve the equation. Write your answer as an integer or simplified fraction.

  • 8n - 7 (n - 2) = 18

<u>Required Solution :</u>

The given equation,

  • 8n - 7 (n - 2) = 18

★ Multiplying -7 into (n - 2),

>> 8n - 7 × (n - 2) = 18

>> 8n - 7n + 14 = 18

★ On substracting 7n from 8n we gets,

>> n + 14 = 18

★ Now transposing 14 which is in L.H.S. into R.H.S. (Remember that sign would be . So 14 would be -14),

>> n = 18 - 14

>> n = 14

★ Therefore,

  • Value of n is 14.

<u>Learn</u><u> more</u><u> from</u><u> brainly</u><u>.</u><u>c</u><u>o</u><u>m</u><u> </u><u>:</u>

brainly.com/question/27432186

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6 0
2 years ago
What is the answer and how do u get that answer
earnstyle [38]
Let me see a better picture
3 0
3 years ago
-24 divided by x + 12 to the second when x= -14
ELEN [110]

Answer:12

Step-by-step explanation:

3 0
3 years ago
Solve for x and y please!
galina1969 [7]

Answer:

x = 8

y=2\sqrt{3}

Step-by-step explanation:

The figure is composed of 3 Right triangles. To find the values of the variables x and y we use the Pythagorean theorem to propose one equation.

x^2 =4^2 + (4\sqrt{3})^2

 Now we solve for x

x=\sqrt{4^2 + (4\sqrt{3})^2}

x=\sqrt{16 +16*3}\\\\x=\sqrt{64}\\\\x=8

Let's call z at the angle opposite to y

Then we have that:

sin(z) =\frac{opposite}{hypotenuse}

Where

hypotenuse = 8

opposite=4

sin(z) =\frac{4}{8}

z=sin^{-1}(\frac{1}{2})

z=30

Now we use this angle to find the length y

sin(z) =\frac{opposite}{hypotenuse}

Where in this case

hypotenuse = 4\sqrt{3}

opposite=y

z=\°30

sin(30\°) =\frac{y}{4\sqrt{3}}

y=sin(30\°)*4\sqrt{3}

y=2\sqrt{3}

6 0
3 years ago
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