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3 years ago

Find the slope of the line will mark as brain

Mathematics

1 answer:

vodka [1.7K]3 years ago

7 0

Answer negative 9 is the answer

Step-by-step explanation:

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Determine the solution to the system of equations below: y = -3x + 6 and 3y = -2x - 3

TiliK225 [7]

Answer:

x = 3

y = -3

Step-by-step explanation:

We have two equations and are asked to solve for x and y.

y = -3x + 6

3y = -2x - 3

Substitute the y in the first equation in the second equation :

3(-3x + 6) = -2x - 3

Distribute :

-9x + 18 = -2x - 3

Solve for x by isolating it :

Subtract 18 from both sides :

-9x = -2x - 21

Add 2x to both sides :

-7x = -21

Divide -7 from both sides :

x = 3

Replace x in the first equation :

y = -3(3) + 6

y = -9 + 6

-9 + 6

y = -3

4 0

3 years ago

(4x + 2), (2x +3), and (x-2)

Lena [83]

The answer is 7x-3 if you add like terms which are 4x, 2x, and x then take 2, 3, -2 and subtract from each other

4 0

2 years ago

Read 2 more answers

If you place a cup of 210 degree Fahrenheit coffee on a table in a room that is 68 degrees fareinheit, and ten minutes later, it

Lana71 [14]

Newton's Law of Cooling

Tf=Ts+(Ti-Ts)e^(-kt) where Tf is temp at time t, Ts is temp of surroundings, Ti is temp of object/fluid. So we need to find k first.

200=68+(210-68)e^(-10k)

132=142e^(-10k)

132/142=e^(-10k)

ln(132/142)=-10k

k=-ln(132/142)/10

k≈0.0073 so

T(t)=68+142e^(-0.0073t) so how long until it reaches 180°?

180=68+142e^(-0.0073t)

112=142e^(-0.0073t)

112/142=e^(-0.0073t)

ln(112/142)=-0.0073t

t= -ln(112/142)/(0.0073)

t≈32.51 minutes

8 0

3 years ago

When the product of 6 and the square of a number is increased by 5 times the number, the result is 4.

Ira Lisetskai [31]

Answer:

Hope this is correct

5 0

3 years ago

Graph ∆KLM with vertices K(2,2), L(0,- 1), and M(-3,2). Graph ∆K'L'M' with a scale factor of 2. What are the coordinates of the

olasank [31]

Answer:

The coordinates of the new vertices are:

K'(4,4), L'(0,- 2), and M'(-6,4).

Step-by-step explanation:

In order to dilate a shape by 2, you can simply multiply the coordinates of the orignal triangle each by 2 to find the new coordinates of the new vertices.

K(2,2), L(0,- 1), and M(-3,2)

K'(2*2,2*2), L'(0*2,- 1*2), and M'(-3*2,2*2).

Now become...

K'(4,4), L'(0,- 2), and M'(-6,4).

You can now graph ∆K'L'M' using these coordinates.

5 0

2 years ago