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ser-zykov [4K]
2 years ago
10

Can someone help me I need help with this question

Mathematics
1 answer:
malfutka [58]2 years ago
4 0
To find the difference of 5 1/8 and 2 1/5 I would first turn the mixed numbers into improper fractions. Therefore, I would have 41/8 - 11/5. Then, I would find a common denominator which would be 40. I would have 205/40 - 88/40 and I would end up with 117/40. 

Can you please help me answer my question? I already asked it but it hasn't been answered. It is fro social studies: What were some accomplishments of Montezuma?
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Part 4. Verbs
Pie

Answer:

MORE STUFF

Step-by-step explanation:

AD STUFF TO STUFF AND YOU GET MORE STUFF

8 0
3 years ago
A carpenter charges $720 for 18 hours of work. She charges the same amount of money for each hour of work.
Rainbow [258]

Answer:

A

Step-by-step explanation:

To start off, you know 18 hours= 720

So you could automatically get rid of B and D since 19 and 17 are not 18.

After that, you have it down to A and C. The way you would find how much she charges for one hour is dividing 720 by 18. When you do that it means you are divding 720$ into 18 different groups each group representing an hour. When you divide 720 by 18 you should get 40. So every hour she makes 40 dollars. 40x 2 hours is 80. I hope I helped you!

3 0
2 years ago
Read 2 more answers
5/6 N=10 solve this problem. I could not put the six under the five where it belongs. please show the work
Andreyy89

5/6N = 10

Mutiply by 6/5

So N=12

3 0
3 years ago
I need help with algebra
rosijanka [135]

Answer:

x = -1 and y = 6

Step-by-step explanation:

using x = -b/2a

x = -4 / 2(2)

x = -1

y = 2(-1)² + 4(-1) + 8

y = 2 - 4 + 8

y = 10 - 4

y = 6

4 0
2 years ago
I need help from uh all..​
DanielleElmas [232]

Answer:

Step-by-step explanation:

Given expression is,

\text{cot}A=\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})

To prove this identity we will take the right side of the identity,

\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})=\frac{1}{2}(\frac{1}{\text{tan}\frac{A}{2}}-tan\frac{A}{2})

                         =\frac{1}{2}(\frac{1-\text{tan}^2\frac{A}{2}}{tan\frac{A}{2}})

                         =\frac{1}{2}[\frac{2(1-\text{tan}^2\frac{A}{2})}{2tan\frac{A}{2}}]

                         =\frac{1}{2}(\frac{2}{\text{tan}A} ) [Since \text{tan}A=\frac{2\text{tan}\frac{A}{2}}{1-\text{tan}^2\frac{A}{2}}]

                         = cot A

Hence right side of the equation is equal to the left side of the equation.

3 0
3 years ago
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