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3 years ago

Which of the scenarios include only independent events?

Mathematics

2 answers:

Marianna [84]3 years ago

6 0

INDEPENDENT IT WAS ON MY TEST

Nadusha1986 [10]3 years ago

4 0

Answer:

Step-by-step explanation:

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Find the equation of the sphere in standard form centered at (−6,10,5) with radius 5.

Dovator [93]

Answer:

The equation of the sphere in standard form is

$x^{2} +y^{2}+z^{2} +12 x-20 y-10 z+136=0$

Step-by-step explanation:

Step 1:-

The equation of the sphere having center and radius is

$(x-h)^{2} +(y-k)^{2} +(z-l)^{2} = r^{2}$

Given centered of the sphere is (-6,10,5) and radius r=5

$(x-(-6))^{2} +(y-10)^{2} +(z-5)^{2} = 5^{2}$

on simplification,we get

$using (a+b)^{2} =a^{2} +2 a b+b^{2}$

$using (a-b)^{2} =a^{2} -2 a b+b^{2}$

simplify , we get

$x^{2} +y^{2}+z^{2} +12 x-20 y-10 z+136=0$

8 0

3 years ago

IT’S TIMED NEED HELP ASAP! Write the relationship between the sides for these two congruent triangles.

wolverine [178]

Answer:

Step-by-step explanation:

They're both right angle triangles and have the same length and size , hence congruency

4 0

3 years ago

Solve for t. -5 − 2t = 3t

allsm [11]

T is equal to -1.

Add 2t to both sides of the equation. -5 = 5t
Divide both sides of the equation by -5. 1 = -t
Multiply both sides of the equation by -1. -1 = t

4 0

3 years ago

Read 2 more answers

ASAP NEEEEED HELLLLLLLLLP PLZZZ

nadya68 [22]

T = 5 a
i = 4% aa
j = 1200
c = ...
j = cit/100
c = 100j / it
c = 100*1200 / 4*5
c = 120000 / 20
c = 12000/2
c = 6000

montante

M = c+j
M = 6000+1200
M = 7200

7 0

3 years ago

Evaluate Dx / ^ 9-8x - x2^

Solnce55 [7]

It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for $\sqrt x$ .

In that case, you want to find the antiderivative,

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}$

Complete the square in the denominator:

$9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2$

Now substitute $x+4=5\sin y$ , so that $\mathrm dx=5\cos y\,\mathrm dy$ . Then

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy$

which simplifies to

$\displaystyle\int\frac{5\cos 
y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy$

Now, recall that $\sqrt{x^2}=|x|$ . But we want the substitution we made to be reversible, so that

$x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)$

which implies that $-\dfrac\pi2\le y\le\dfrac\pi2$ . (This is the range of the inverse sine function.)

Under these conditions, we have $\cos y\ge0$ , which lets us reduce $\sqrt{\cos^2y}=|\cos y|=\cos y$ . Finally,

$\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C$

and back-substituting to get this in terms of $x$ yields

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C$

4 0

3 years ago