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AlekseyPX
2 years ago
10

5x-11=3x+5 solve for ”x”

Mathematics
1 answer:
I am Lyosha [343]2 years ago
4 0

Answer:

x = 8

Step-by-step explanation:

Step 1: Write equation

5x - 11 = 3x + 5

Step 2: Solve for <em>x</em>

<u>Subtract 3x on both sides:</u> 2x - 11 = 5

<u>Add 11 to both sides:</u> 2x = 16

<u>Divide both sides by 2:</u> x = 8

Step 3: Check

<em>Plug in x to verify it is a solution.</em>

5(8) - 11 = 3(8) + 5

40 - 11 = 24 + 5

29 = 29

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5/8=X/28 Find the value of x in the following proportions.
Leno4ka [110]

Answer:

x = 17.5

Step-by-step explanation:

5/8 = x/28

=> 5(28) = 8x

=> 140 = 8x

=> 8x = 140

=> x = 140/8

=> x = 70/4

=> x = 35/2

=> x = 17.5

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2 years ago
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Use any method to solve the system of equations.<br> 3x + 4y = 12<br> 2x + 3y = 10<br> Solve for y.
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3 years ago
Given the function f(x) = 5^x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3. Part A: Find the average r
Wewaii [24]
Table of the graph:
x: <em></em>1  2    3 
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Find the missing measure in the triangle below.
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From a window 20 feet above the ground, the angle of elevation to the top of a building across
Nikitich [7]

Answer: The answer is 381.85 feet.

Step-by-step explanation:  Given that a window is 20 feet above the ground. From there, the angle of elevation to the top of a building across  the street is 78°, and the angle of depression to the base of the same building is 15°. We are to calculate the height of the building across the street.

This situation is framed very nicely in the attached figure, where

BG = 20 feet, ∠AWB = 78°, ∠WAB = WBG = 15° and AH = height of the bulding across the street = ?

From the right-angled triangle WGB, we have

\dfrac{WG}{WB}=\tan 15^\circ\\\\\\\Rightarrow \dfrac{20}{b}=\tan 15^\circ\\\\\\\Rightarrow b=\dfrac{20}{\tan 15^\circ},

and from the right-angled triangle WAB, we have'

\dfrac{AB}{WB}=\tan 78^\circ\\\\\\\Rightarrow \dfrac{h}{b}=\tan 15^\circ\\\\\\\Rightarrow h=\tan 78^\circ\times\dfrac{20}{\tan 15^\circ}\\\\\\\Rightarrow h=361.85.

Therefore, AH = AB + BH = h + GB = 361.85+20 = 381.85 feet.

Thus, the height of the building across the street is 381.85 feet.

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3 years ago
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