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3 years ago

5x-11=3x+5 solve for ”x”

Mathematics

1 answer:

I am Lyosha [343]3 years ago

4 0

Answer:

x = 8

Step-by-step explanation:

Step 1: Write equation

5x - 11 = 3x + 5

Step 2: Solve for x

Subtract 3x on both sides: 2x - 11 = 5

Add 11 to both sides: 2x = 16

Divide both sides by 2: x = 8

Step 3: Check

Plug in x to verify it is a solution.

5(8) - 11 = 3(8) + 5

40 - 11 = 24 + 5

29 = 29

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Factor n 3 - n 2 + 3n - 3.

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3 years ago

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Please help me using product rule

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Using the product rule, then (A) is the answer.

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3 years ago

Identify the sequence as arithmetic, geometric, both, or neither. 50, –50, 50, –50, . . . both arithmetic geometric neither desc

stellarik [79]

Answer:

The sequence is geometric.

Step-by-step explanation:

In Arithmetic sequence, there is a common difference between any two consecutive terms but in Geometric sequence, there is a common ratio between any two consecutive terms.

Given sequence is: 50, -50, 50, -50,.................

Lets assume, the terms as $a_{1}, a_{2}, a_{3}, a_{4},...........$

Checking for common difference:

$a_{2}-a_{1}= (-50)-(50)= -100\\ \\ a_{3}-a_{2}=(50)-(-50)=100\\ \\ a_{4}-a_{3}=(-50)-(50)=-100$

As there is no common difference, so it's not an arithmetic sequence.

Checking for common ratio

$\frac{a_{2}}{a_{1}}=\frac{-50}{50}=-1\\ \\ \frac{a_{3}}{a_{2}}=\frac{50}{-50}=-1\\ \\ \frac{a_{4}}{a_{3}}=\frac{-50}{50}=-1$

As there is a common ratio, so it's a geometric sequence.

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4 years ago

Work out the value of 7^2-3^3

kow [346]

Answer:

Step-by-step explanation:

7^2=49

3^3=27

49-27=22

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3 years ago

3. For the polynomial: ()=−2(+19)3(−14)(+3)2, do the following:A. Create a table of values that have the x-intercepts of p(x) in

Pepsi [2]

Part A. We are given the following polynomial:

$\mleft(\mright)=-2\mleft(+19\mright)^3\mleft(-14\mright)\mleft(+3\mright)^2$

This is a polynomial of the form:

$p=k(x-a)^b(x-c)^d\ldots(x-e)^f$

The x-intercepts are the numbers that make the polynomial zero, that is:

$\begin{gathered} p=0 \\ (x-a)^b(x-c)^d\ldots(x-e)^f=0 \end{gathered}$

The values of x are then found by setting each factor to zero:

$\begin{gathered} (x-a)=0 \\ (x-c)=0 \\ \text{.} \\ \text{.} \\ (x-e)=0 \end{gathered}$

Therefore, this values are:

$\begin{gathered} x=a \\ x=c \\ \text{.} \\ \text{.} \\ x=e \end{gathered}$

In this case, the x-intercepts are:

$\begin{gathered} x=-19 \\ x=14 \\ x=-3 \end{gathered}$

The multiplicity are the exponents of the factor where we got the x-intercept, therefore, the multiplicities are:

Part B. The degree of a polynomial is the sum of its multiplicities, therefore, the degree in this case is:

$\begin{gathered} n=3+1+2 \\ n=6 \end{gathered}$

To determine the end behavior of the polynomial we need to know the sign of the leading coefficient that is, the sign of the coefficient of the term with the highest power. In this case, the leading coefficient is -2, since the degree of the polynomial is an even number this means that both ends are down. If the leading coefficient were a positive number then both ends would go up. In the case that the leading coefficient was positive and the degree and odd number then the left end would be down and the right end would be up, and if the leading coefficient were a negative number and the degree an odd number then the left end would be up and the right end would be down.

Part C. A sketch of the graph is the following:

If the multiplicity is an odd number the graph will cross the x-axis at that x-intercept and if the multiplicity is an even number it will tangent to the x-axis at that x-intercept.

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2 years ago