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ANTONII [103]
4 years ago
12

The formula to find the period of orbit of a satellite around a planet is T^2=(4pi^2/GM)r^3 where r is the orbit's mean radius,

M is the mass of the planet, and G is the universal gravitational constant. if you are given all the values except r, how do you rewrite the formula to solve for r?
Mathematics
2 answers:
Bess [88]4 years ago
5 0

Answer:so whats the answer????

Step-by-step explanation:

Natalija [7]4 years ago
3 0
The answer is r= \sqrt[3]{GMT^{2}/4 \pi^{2}}

T^{2} = \frac{4 \pi^{2}}{GM} r^{3}

Move \frac{4 \pi^{2} }{GM} to the other side of the equation:
T^{2} /\frac{4 \pi^{2} }{GM} = r^{3}  \\ 
T^{2} *\frac{GM}{4 \pi^{2} } = r^{3}

Rearrange:
r^{3} = T^{2} *\frac{GM}{4 \pi^{2} } \\ 
r^{3}= \frac{T^{2} *GM}{4 \pi^{2} }  \\ 
r^{3}= \frac{GMT^{2}}{4 \pi^{2} } \\ 
r^{3} = GMT^{2}/4 \pi^{2}

Since x^{3}= \sqrt[3]{x}, then
r^{3} = GMT^{2}/4 \pi^{2} \\ 
r= \sqrt[3]{GMT^{2}/4 \pi^{2}}
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Answer:-2-1

Step-by-step explanation:

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Which choice could be the equation of a line parallel to the line represented by this equation y=2x-3
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"The volume of the trapezoidal prism is 1279.152 cubic feet. Determine the height of the trapezoidal base"
Diano4ka-milaya [45]

Answer:

The height of the trapezoidal base is 7.2 ft.

Step-by-step explanation:

Consider the provided information.

The volume of trapezoidal prism is the area of the cross-section × the length.

V=BH

Where B is the area of base, H is the length and V is the volume.

The length of the prism is 25.2ft and volume is 1279.152

1279.152=B(25.2)

B=50.76

Hence, the base area is 50.76 ft².

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Substitute B=50.76, b_1=10\ and\ b_2=4.1 in above formula.

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4 0
3 years ago
Can someone help me with this
Alexxandr [17]

Answer:

Line 1: -2

Line 2: 2

Line 3: 2

Line 1 & 2 is parallel.

Line 2 & 3 is neither.

Step-by-step explanation:

To find the slope of a line use the slope formula and substitute the points into it:

Line 1

m = \frac{y_2-y_1}{x_2-x_1} =\frac{2--2}{0-2} =\frac{2+2}{-2} =\frac{4}{-2}=-2

Line 2

m = \frac{y_2-y_1}{x_2-x_1} =\frac{-5--1}{1--1} =\frac{-5+1}{1+1} =\frac{-4}{2}= -2

Line 3

m = \frac{y_2-y_1}{x_2-x_1} =\frac{0--4}{-3--5} =\frac{0+4}{-3+5} =\frac{4}{2}=2

Parallel lines have the same slope and perpendicular lines have negative reciprocal slopes.

Line 1 & 2 is parallel.

Line 2 & 3 is neither.

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3 years ago
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Step-by-step explanation:

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