What's the probability of obtaining a 3 digit number at random which is DIVISIBLE by 7
1 answer:
You might be interested in
Answer:
a ) See Annex
b) P₁ = 0,0464 or P₁ = 4,64 %
c) P₄ = 0,92 or P₄ = 92 %
Step-by-step explanation:
b) P₁ [ X being defective ] = P₂ + P₃
Where P₂ is the probability of X rays machine detects a weld defective and the weld is really defective
And P₃ is the probability of X rays machine detects a weld defective and the weld is not defective
Then
P₂ = 0,04 * 0,92 = 0,0368
P₃ = 0,96 * 0,01 = 0,0096
Then P₁ = 0,0368 + 0,0096
P₁ = 0,0464 or P₁ = 4,64 %
c) P₄ = 0,04 *0,92
P₄ = 0,92 or P₄ = 92 %
