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nikitadnepr [17]

3 years ago

9

What are the possible side lengths of a triangle

2 answers:

ololo11 [35]3 years ago

8 0

NONE of those lengths will form a triangle.
Basically, the longest side of a triangle must be less than the sum of the other 2 sides. In this case NONE of those choices will form a triangle.

BartSMP [9]3 years ago

4 0

Hey!
So to find this you have to add the 2 smaller lengths and see if they are larger than the largest length.
3 + 5 is 8 and that is not greater than 9 so A is wrong
4 + 8 is 12 and it is larger than 10, so maybe...
6 + 9 is 15 and that is not larger than 17 so that is out
8+10 is 18 and that is equal to but not larger than 18 so that is out
Your answer is B!
Hope this helps!

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Alisiya [41]

Answer:

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Step-by-step explanation:

In this equation, a=5, b=-1, c=-4.

Plug these into the quadratic formula:

x = $\frac{1+\sqrt{-1^{2}-(-4)(5)(-4) } }{2(5)}$ and x = $\frac{1-\sqrt{-1^{2}-(-4)(5)(-4) } }{2(5)}$

Now, simplify the equations:

x = $\frac{1+\sqrt{81} }{10}$ = $\frac{1+9}{10}$ = $\frac{10}{10}$ = 1

and

x = $\frac{1-\sqrt{81} }{10}$ = $\frac{1-9}{10}$ = $\frac{-8}{10}$ = $\frac{-4}{5}$

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3 years ago

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3 years ago

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lana66690 [7]

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Step-by-step explanation:

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