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3 years ago

Write a word problem that you can represent with the expression 8 divided by 2/3

Mathematics

1 answer:

antoniya [11.8K]3 years ago

8 0

I had 8 tampons this morning but 2/3 of the girls in my class got their period and now I’m out of tampons

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If parallelogram RSTV has diagonals then RSTV must also be a _______. square and a rectangle rhombus and a rectangle rhombus rec

andrew11 [14]

a rectangle rhombus(parallelogram) since even a parallelogram has diagonals

5 0

3 years ago

Fifty- three students from 32 different schools signed up for a multi-classroom project. About how many students signed up for t

inessss [21]

Hello there.

Fifty- three students from 32 different schools signed up for a multi-classroom project. About how many students signed up for the project?

B. about 1,800 students

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2 years ago

Read 2 more answers

Between x=2 and x=3, which function has a greater average rate of change than f(x)=2^x has?

maxonik [38]

Answer: f(3)

Step-by-step explanation:

First find the formula for the rate of change by taking the derivative of 2^x. Let f(x) equal some hypothetical y-value, then take the natural log of both sides.

$y=2^x\\\ln(y)=x \ln(2)$

Implicitly differentiate the left side and take the derivative of the right side

$\frac{y'}{y} =\ln(2)$

Multiply both sides by 'y' which was defined as 2^x

$y'=\ln(2)*2^x$

Plug in x = 2 and x = 3 to see which slope is larger

$y'=\ln(2)*2^2=4\ln(2)\\y'=\ln(2)*2^3=8\ln(2)$

4 0

3 years ago

What is the slope of the line through -7,-8 and (0,4)?

Sphinxa [80]

Answer:

A: 12/7

Step-by-step explanation:

4 0

2 years ago

Solve 2cos ²y -siny -1=0 for 0° ≤y≤360°

natima [27]

$\displaystyle\bf\\2cos^2y -sin\,y -1=0~~~for~~0^o\leq y \leq360^o\\\\cos^2y=1-sin^2y\\\\2(1-sin^2y) -sin\,y -1=0\\\\2-2sin^2y-sin\,y-1=0\\\\-2sin^2y-sin\,y+2-1=0\\\\-2sin^2y-sin\,y+1=0~~~\Big|\times(-1)\\\\2sin^2y+sin\,y-1=0$

$\displaystyle\bf\\\boxed{\bf sin\,y=x}\\\\2x^2+x-1=0\\\\x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-1\pm\sqrt{1-4\cdot2\cdot(-1)}}{2\cdot2}=\\\\=\frac{-1\pm\sqrt{1+8}}{4}=\frac{-1\pm\sqrt{9}}{4}=\frac{-1\pm3}{4}\\\\x_1=\frac{-1+3}{4}=\frac{2}{4}=\boxed{\bf\frac{1}{2}}\\\\x_2=\frac{-1-3}{4}=\frac{-4}{4}=\boxed{\bf-1}\\\\sin\,y=\frac{1}{2}\\\\\boxed{\bf y_1=\frac{\pi}{6}~~or~~(30^o)}\\\\\boxed{\bf y_2=\frac{5\pi}{6}~~or~~(150^o)}\\\\sin\,y=-1\\\\\boxed{\bf y_3=\frac{3\pi}{2}~~or~~(270^o)}$

5 0

2 years ago