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olchik [2.2K]
3 years ago
15

What is the mode of the following numbers? 9, 10, 6, 5, 69,10,6,5,6

Mathematics
2 answers:
-BARSIC- [3]3 years ago
8 0
The mode would be 6 because it is in the numbers more than any number

mash [69]3 years ago
6 0
6 is the mode since it appears the most, 3 times 
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Solve the following inequaltity. (x-8)^2(x+7)>0 What is the solution?
GREYUIT [131]

(x-8)^2(x+7)>0 \\x\in(-7,8)

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3 years ago
According to government data, 75% of employed women have never been married. Rounding to 4 decimal places, if 15 employed women
blagie [28]

Answer:

We are given that According to government data, 75% of employed women have never been married.

So, Probability of success = 0.75

So, Probability of failure = 1-0.75 = 0.25

If 15 employed women are randomly selected:

a. What is the probability that exactly 2 of them have never been married?

We will use binomial

Formula : P(X=r) =^nC_r p^r q^{n-r}

At x = 2

P(X=r) =^{15}C_2 (0.75)^2 (0.25^{15-2}

P(X=2) =\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{13}

P(X=2) =8.8009 \times 10^{-7}

b. That at most 2 of them have never been married?

At most two means at x = 0 ,1 , 2

So,  P(X=r) =^{15}C_0 (0.75)^0 (0.25^{15-0}+^{15}C_1 (0.75)^1 (0.25^{15-1}+^{15}C_2 (0.75)^2 (0.25^{15-2}

 P(X=r) =(0.75)^0 (0.25^{15-0}+15 (0.75)^1 (0.25^{15-1}+\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{15-2})

P(X=r) =9.9439 \times 10^{-6}

c. That at least 13 of them have been married?

P(x=13)+P(x=14)+P(x=15)

={15}C_{13}(0.75)^{13} (0.25^{15-13})+{15}C_{14} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})

=\frac{15!}{13!(15-13)!}(0.75)^{13} (0.25^{15-13})+\frac{15!}{14!(15-14)!} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})

=0.2360

8 0
3 years ago
What are the solutions to the equation f(x)= g(x)?
PIT_PIT [208]

Answer:

2 solutions

Step-by-step explanation:

We are given the equations of f(x) and g(x).

To find f(x) = g(x), we just let those two equations equal each other

x^{2} -4x+5=x+1

Group all like terms,

x^{2} -3x+4=0

Factorise,

(x-4)(x+1)=0

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Hope this helped!!

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How do the magnetic and electrical components of electromagnetic waves travel in relation to each other ?
pashok25 [27]

Answer:

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Hope this helps.

Step-by-step explanation:

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Answer:

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2×+34-34=4-34

2×=4-34

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2×/2=-30/2

×= -15

5 0
2 years ago
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