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viva [34]
3 years ago
9

In hunter-gather societies most hunting was done by

Computers and Technology
2 answers:
Tanya [424]3 years ago
5 0

the answer to this was men

suter [353]3 years ago
3 0

In hunter-gather societies most hunting was done by Men

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Write a program that can print a banner with rotated letters, such that they can be read from top to bottom. Specifically, each
My name is Ann [436]

Answer:

package Lab6Problema;

import java.util.Scanner;

public class Lab6Problema{

public static void H() // prints H

{

System.out.println();

System.out.println("** **");

System.out.println("** **");

System.out.println("******");

System.out.println("** **");

System.out.println("** **");

}

 

public static void E()//prints E

{

System.out.println();

System.out.println("******");

System.out.println("** ");

System.out.println("******");

System.out.println("** ");

System.out.println("******");

}

 

public static void L()//prints L

{

System.out.println();

System.out.println("* ");

System.out.println("* ");

System.out.println("* ");

System.out.println("* ");

System.out.println("******");

}

 

public static void O()//prints O

{

System.out.println();

System.out.println("******");

System.out.println("* *");

System.out.println("* *");

System.out.println("* *");

System.out.println("******");

}

 

public static void W()//prints W

{

System.out.println();

System.out.println("* *");

System.out.println("* *");

System.out.println("* ** *");

System.out.println("* ** *");

System.out.println("** **");

}

 

public static void R()//prints R

{

System.out.println();

System.out.println("***** ");

System.out.println("** **");

System.out.println("***** ");

System.out.println("** **");

System.out.println("** **");

}

 

public static void D()//prints D

{

System.out.println();

System.out.println("**** ");

System.out.println("* * ");

System.out.println("* *");

System.out.println("** * ");

System.out.println("**** ");

}

public static void blank() //prints blank space

{

System.out.println();

System.out.println();

System.out.println();

}

public static void main(String[] args) {

//just enter "Hello World" as input as specified

System.out.println("Enter a Message");

Scanner scan=new Scanner(System.in);

String myMessage=scan.nextLine(); // read msg using scanner

int numOfCharacters=myMessage.length();// calculate message lenth

for(int i=0;i<numOfCharacters;i++) // loop through each chracter in msg

{

// gets character at position i, and switch accordingly

switch(myMessage.charAt(i))

{

// if character is 'H' or 'h', call method H(). Similarly for other

// Hecharacters in message.

case 'H':

case 'h':H();break;

case 'E':

case 'e':E();break;

case 'L':

case 'l':L();break;

case 'O':

case 'o':O();break;

case 'W':

case 'w':W();break;

case 'R':

case 'r':R();break;

case 'D':

case 'd':D();break;

case ' ':blank();break;

}

}

}

}

Explanation:

4 0
3 years ago
HTML, the markup language of the web, specifies colors using the RGB model. It uses a two-digit hexadecimal (that is, base 16) r
Sveta_85 [38]

Solution :

It is given that :

The digits 0 through 9 in hexadecimal have their usual meanings. But letters A through F function like the digits and it means digits 10 through 15, respectively.

Now the base of a hexadecimal is 16.

Now we know from 0 to 9  $\rightarrow$ A, B, C, D, E, F

Now the maximum two digits hexadecimal numbers are =  F F

So, F F  $= 16 \times 15 + 16^0 \times 15$

            = 255

6 0
3 years ago
What does confidentiality of data refer to?
tekilochka [14]

d) Rules which restrict access only to those who need to know
4 0
3 years ago
Read 2 more answers
How to delete a bucket in microsoft planner
katrin2010 [14]
You can just click file and delete
7 0
3 years ago
On a piano, each key has a frequency, and each subsequent key (black or white) is a known amount higher. Ex: The A key above mid
lora16 [44]

Answer:

sample output

Enter f0 = 440

440.0,466.1637615180899, 493.8833012561241,

523.2511306011974,  554.3652619537443

Explanation:

import math                                 // math library  

def RaiseToPower():                 //  RaiseToPower method

 r = math.pow(2,1/12)               //r = 2^(1/12)

f0 = float(input('Enter f0 : '))     //input from user

                                               

//a key has a frequency,sy f0

                                                                                                                                     

print(f0,end=' ')                      //Display statement

 for n in range(1,5):                //Iterate the loop up to  the next 4 higher key Hz

n = f0 * math.pow(r,n)         //calculate the fn value

print(fn,end=' ')                   //Display statement

 RaiseToPower()                //Call RaiseToPower method  

                                         

 

         

     

       

7 0
4 years ago
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