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2 years ago

Why people like adventures

Computers and Technology

1 answer:

OLEGan [10]2 years ago

3 0

A lot of people do love going on different kinds of adventures. People do like adventures because;

It helps to improve their physical health and it also hinders/ treat different scope or range of health issues.

It helps to make the human brain bigger that is, adventures such as hiking or walking helps to grow the brains.

People go on adventures so as to build or raise their tolerance level such as Tolerance for uncertainty.

Adventures helps to improve one's reflectiveness and mental skill
It gives you new ideas, feeds your dreams and also helps to builds your confidence.

Adventure is simply defined as the act of been involved in an unusual or exciting experience or any activity. It can be hazardous in nature.

Learn more about adventure from

brainly.com/question/25950911

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Oxnard Casualty wants to ensure that their e-mail server has 99.98 percent reliability. They will use several independent server

sattari [20]

Answer:

The smallest number of servers required is 3 servers

Explanation:

Given

$Reliability = 99.98\%$

$Individual Servers = 95\%$

Required

Minimum number of servers needed

Let p represent the probability that a server is reliable and the probability that it wont be reliable be represented with q

Such that

$p = 95\%\\$

It should be noted that probabilities always add up to 1;

So,

$p + q = 1$ '

Subtract p from both sides

$p - p + q = 1 - p$

$q = 1 - p$

Substitute $p = 95\%\\$

$q = 1 - 95\%$

Convert % to fraction

$q = 1 - \frac{95}{100}$

Convert fraction to decimal

$q = 1 - 0.95$

$q = 0.05$

------------------------------------------------------------------------------------------------

To get an expression for one server

The probabilities of 1 servers having 99.98% reliability is as follows;

$p = 99.98\%$

Recall that probabilities always add up to 1;

So,

$p + q = 1$

Subtract q from both sides

$p + q - q = 1 - q$

$p = 1 - q$

So,

$p = 1 - q = 99.98\%$

$1 - q = 99.98\%$

Let the number of servers be represented with n

The above expression becomes

$1 - q^n = 99.98\%$

Convert percent to fraction

$1 - q^n = \frac{9998}{10000}$

Convert fraction to decimal

$1 - q^n = 0.9998$

Add $q^n$ to both sides

$1 - q^n + q^n= 0.9998 + q^n$

$1 = 0.9998 + q^n$

Subtract 0.9998 from both sides

$1 - 0.9998 = 0.9998 - 0.9998 + q^n$

$1 - 0.9998 = q^n$

$0.0002 = q^n$

Recall that $q = 0.05$

So, the expression becomes

$0.0002 = 0.05^n$

Take Log of both sides

$Log(0.0002) = Log(0.05^n)$

From laws of logarithm $Loga^b = bLoga$

So,

$Log(0.0002) = Log(0.05^n)$ becomes

$Log(0.0002) = nLog(0.05)$

Divide both sides by $Log0.05$

$\frac{Log(0.0002)}{Log(0.05)} = \frac{nLog(0.05)}{Log(0.05)}$

$\frac{Log(0.0002)}{Log(0.05)} = n$

$n = \frac{Log(0.0002)}{Log(0.05)}$

$n = \frac{-3.69897000434}{-1.30102999566}$

$n = 2.84310893421$

$n = 3 (Approximated)$

Hence, the smallest number of servers required is 3 servers

6 0

3 years ago

Doe's anyone know how to access developer mode on a Chromebook laptop if enterprise enrollment blocks it?

Mekhanik [1.2K]

♥ Boot your Chromebook into recovery Mode
(Escape refresh and power keys all need to be help down)
It will then reboot into recovery mode
♥ Press Ctrl+D at the recovery screen
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♥ and then you have it :D

8 0

3 years ago

Read 2 more answers

Write a program that will predict the size of a population of organisms. The program should ask the user for the starting number

sineoko [7]

Answer:

// using c++ language

#include "stdafx.h";

#include <iostream>

#include<cmath>

using namespace std;

//start

int main()

{

//Declaration of variables in the program

double start_organisms;

double daily_increase;

int days;

double updated_organisms;

//The user enters the number of organisms as desired

cout << "Enter the starting number of organisms: ";

cin >> start_organisms;

//Validating input data

while (start_organisms < 2)

{

cout << "The starting number of organisms must be at least 2.\n";

cout << "Enter the starting number of organisms: ";

cin >> start_organisms;

}

//The user enters daily input, here's where we apply the 5.2% given in question

cout << "Enter the daily population increase: ";

cin>> daily_increase;

//Validating the increase

while (daily_increase < 0)

{

cout << "The average daily population increase must be a positive value.\n ";

cout << "Enter the daily population increase: ";

cin >> daily_increase;

}

//The user enters number of days

cout << "Enter the number of days: ";

cin >> days;

//Validating the number of days

while (days<1)

{

cout << "The number of days must be at least 1.\n";

cout << "Enter the number of days: ";

cin >> days;

}

//Final calculation and display of results based on formulas

for (int i = 0; i < days; i++)

{

updated_organisms = start_organisms + (daily_increase*start_organisms);

cout << "On day " << i + 1 << " the population size was " << round(updated_organisms)<<"."<<"\n";

start_organisms = updated_organisms;

}

system("pause");

return 0;

//end

}

Explanation:

6 0

3 years ago

Write a SELECT statement that returns these three columns: vendor_nameThe vendor_name column from the Vendors table default_acco

Sati [7]

Explanation:

"Select vendor_name as Vendor_Name,

default_account_number as Default_Account_No ,

account_description as Account_Description

From Vendors v, General_Ledger_Accounts ledger

where (add the join condition here)

Order by account_description, vendor_name"

Note: In the above statement, include the alias name appropriately and then execute the query

The "select statement" should contain the list of columns to be displayed

"From statement" should contain the name of the table from which data needs to be fetched.

"Where clause" defines the relationship as well the condition that needs to be executed

"Order by clause" defines the sorting mechanism with the relevant field

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3 years ago

What is a feature of Accenture’s myNav platform?

ZanzabumX [31]

C because I said so hahahah

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3 years ago

Why people like adventures ​

Why people like adventures