Answer:
Yes, it would be unusual.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean  and standard deviation
 and standard deviation  , the zscore of a measure X is given by:
, the zscore of a measure X is given by:
 
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
If  or
 or  , the outcome X is considered unusual.
, the outcome X is considered unusual. 
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean  and standard deviation
 and standard deviation  , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean  and standard deviation
 and standard deviation  .
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this question, we have that:

Would it be unusual for this sample mean to be less than 19 days?
We have to find Z when X = 19. So
 
By the Central Limit Theorem
 

 , so yes, the sample mean being less than 19 days would be considered an unusual outcome.
, so yes, the sample mean being less than 19 days would be considered an unusual outcome.