All categories

2 years ago

❗❗100points❗❗

2 answers:

7 0

The cell is the smallest structural and functional unit of living organisms, which can exist on its own. Therefore, it is sometimes called the building block of life. Some organisms, such as bacteria or yeast, are unicellular—consisting only of a single cell—while others, for instance, mammalians, are multicellular.

kotykmax [81]2 years ago

6 0

Answer:

Answer: Sample Response: The height of the triangle will be twice the height of the rectangle. The area of a triangle is ½ bh and the area of a rectangle is bh. If the bases are the same, then the height of the triangle has to be double that of the rectangle in order to get the same area.

Step-by-step explanation:

You might be interested in

719 = (78 × 9) + ____ find the unknown number

viva [34]

Answer: 17

Step-by-step explanation:

78 x 9

=702

702 -719

= 17

4 0

3 years ago

Read 2 more answers

What is the interest amount after borrowing $83,500 at a rate of 4.005% over 6 years? Round your answer to the nearest cent.

nadya68 [22]

Answer:

83,000

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y

irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

$y'(x)= x^2y(x)-\frac12y^2(x)$

Putting the value of y'(x) in equation (1)

$y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))$

Substituting x =0 and h= 0.2

$y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]$

$\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]$ [∵ y(0) =3 ]

$\Rightarrow y(0.2)\approx 2.7$

Substituting x =0.2 and h= 0.2

$y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]$

$\Rightarrow y(0.4)\approx 2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]$

$\Rightarrow y(0.4)\approx 1.9926$

Substituting x =0.4 and h= 0.2

$y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]$

$\Rightarrow y(0.6)\approx 1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]$

$\Rightarrow y(0.6)\approx 1.6593$

Substituting x =0.6 and h= 0.2

$y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]$

$\Rightarrow y(0.8)\approx 1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]$

$\Rightarrow y(0.6)\approx 0.8800$

Substituting x =0.8 and h= 0.2

$y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]$

$\Rightarrow y(1.0)\approx 0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]$

$\Rightarrow y(1.0)\approx 0.9152$

Therefore the value of y(1)= 0.9152.

4 0

3 years ago

What is the equation of the line that passes through (2, 7) and is perpendicular to y= -5

timofeeve [1]

Answer:

x = 2

Step-by-step explanation:

y = - 5 is a horizontal line parallel to the x- axis.

A line perpendicular to it will be a vertical line parallel to the y- axis with equation

x = c

Where c is the value of the x- coordinates the line passes through.

The line passes through (2, 7) with an x- coordinate of 2, thus

x = 2 ← is the equation of the perpendicular line

5 0

3 years ago

What is 8÷3 rounded to the nearest 10th

Volgvan

8÷3 is 2.666666667, 6 is greater than 5 so rounded to the nearest tenth it is 2.7

6 0

3 years ago