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mel-nik [20]
3 years ago
13

Can somebody help solve either of these?

Mathematics
1 answer:
Leya [2.2K]3 years ago
8 0
First one:
The circumference of the whole circle is (2π x the radius), 
and 60° is (60/360) = 1/6 of the whole circumference.

Second one:
The area of the whole circle is (π x the radius²), and
the 40° sector is (40/360) = 1/9 of the whole area.

I hope this is enough help.
You might be interested in
Please help me I dont understand any of this. Ps it might take me a while for me to understand. :/
Tems11 [23]

How to clear an equation/solve for any given variable?

Lets say you have two identical cups of coffee, a and b.

You can say they're both equal. If you want to add a tablespoon of sugar to cup a, and you also want both cups to remain equal, you'll have to add the same tablespoon of sugar to cup b.

We use this fact, called conservation of an equality, to clear an equation (A.K.A solving for a variable)

Mathematically speaking,

<em>Cups </em>a <em>and </em>b<em> are equal</em>

a=b

<em>If you modify </em>a<em>, you'll have to modify </em>b <em>the same way</em>

\begin{gathered} a+3=b+3 \\ a-1=b-1 \\ a\times4=b\times4 \\ \frac{a}{5}=\frac{b}{5} \end{gathered}

Now, let's apply that logic to the equation we have.

We know cup of coffee a is

6y-1.5x

And cup b is

8

We also know both cups of coffee are equal, so

6y-1.5x=8

We're being asked to solve for y. In other words, we have to clear y from this expression.

Let's add our first tablespoon of sugar: adding 1.5x to both sides:

\begin{gathered} 6y-1.5x=8\rightarrow6y-1.5x+1.5x=8+1.5x \\ \rightarrow6y=8+1.5x \end{gathered}

See how the -1.5x canceled out? That's what we're looking for! We want y to be left alone in its side.

Now, let's divide both sides by 6 to cancel out the 6 from 6y:

\begin{gathered} 6y=8+1.5x\rightarrow\frac{6y}{6}=\frac{8+1.5x}{6} \\ \rightarrow y=\frac{8+1.5x}{6} \\ \rightarrow y=\frac{8}{6}+\frac{1.5}{6}x \\ \rightarrow y=1.33+0.25x \end{gathered}

He have cleared y / solved the equation for y

<em>Let's try with another example</em>

<em />

e.g:

<em>Solve the following equation for </em>b

3b+9a+12=6

Solution: Let's substract 12 from both sides:

\begin{gathered} 3b+9a+12=6\rightarrow3b+9a+12-12=6-12 \\ \rightarrow3b+9a=-6 \end{gathered}

Then, let's substract 9a from both sides

\begin{gathered} 3b+9a=-6\rightarrow3b+9a-9a=-6-9a \\ \rightarrow3b=-6-9a \end{gathered}

Let's divide both sides by 3

\begin{gathered} 3b=-6-9a\rightarrow\frac{3b}{3}=-\frac{6}{3}-\frac{9a}{3} \\ \rightarrow b=-2-3a \end{gathered}

8 0
1 year ago
Determine whether the given segments have the same length. Complete the justification of your answer,
Ratling [72]

Answer:

No does not contain the same length

Step-by-step explanation:

Given that

A(-4,2) , B (1,4), C (2, -1)

Now

AB would be

= \sqrt{(1-(-4))^2 + (4-2)^2} \\\\= \sqrt{29}

And, BC is

= \sqrt{(2-1)^2 + 1-(-4))^2} \\\\= \sqrt{26}

As we can see that the AB and BC are not equaled

So,

AB ≠ BC

Due to the different length

Therefore they do not contains the same length

We simply applied the distance formula due to which the length could be determined and the same is to be considered

5 0
3 years ago
Help please can’t find answers anywhere
Jobisdone [24]

Answer:

They are not equal to each other

Step-by-step explanation:

3^2 + 2^2 = C^2

9+4=C^2

13=c^2

3.6= CD

2^2 +2^2 =c^2

4+4 =c^2

8=c^2

2.8= EF

8 0
3 years ago
Read 2 more answers
What is the vertex of the quadratic function f(x) = (x – 8)(x – 2)?
LekaFEV [45]
Something funny is that the x value of the vertex lies directl in the middle of the x intercepts
so
we see the x intercepts or 0's at x=8 and 2
the average is x=5
so find f(5) to find the y value of the vertex
f(5)=(5-8)(5-2)
f(5)=(-3)(3)
f(5)=-9

vertex is at (5,-9)

the actual way the teacher wants is to expand then compltete the square to get into the form f(x)=a(x-h)^2+k where the vertex is (h,k)
but whatever


verrtex is at (5,-9)
7 0
4 years ago
25 POINTS!!!!Which of the following statements are true? Select all that apply.
ella [17]

Answer:

A+B=B+A

B+0=B

E-C=E+(-C)

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
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