Question number 10 please answer fast it is urgent

Find the value of n so that the expression is a perfect square trinomial and then factor the trinomial.

Anna007 [38]

The correct expression is (a) n = 100; (x + 10)^2

<h3>How to determine the value of n?</h3>

The expression is given as:

x^2 + 20x + n

Take the coefficient of x

k = 20

Divide by 2

k/2= 10

Square both sides

(k/2)^2 = 100

The above value represents the value of n

i.e.

n = 100

So, we have:

x^2 + 20x + 100

Expand

x^2 + 10x + 10x + 100

Factorize

x(x + 10) + 10(x + 10)

Factor out x + 10

(x + 10)^2

Hence, the correct expression is (a) n = 100; (x + 10)^2

Read more about trinomial at:

brainly.com/question/1538726

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7 0

2 years ago

Which equation is represented by Ms. Wilson’s model

SVEN [57.7K]

D Q

TC = D x P + ___ x Cp + ____ x Cs

Q 2

TC: Total Cost

P: Price per unit

Q: Quantity

Cp: Cost of issuance of a purchase order

Cs: storage cost per unit

7 0

3 years ago

Find T5(x) : Taylor polynomial of degree 5 of the function f(x)=cos(x) at a=0 . (You need to enter function.) T5(x)= Find all va

Burka [1]

Answer:

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

The polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

Step-by-step explanation:

According to Taylor's theorem

$\bf f(x)=f(0)+f'(0)x+f''(0)\displaystyle\frac{x^2}{2}+f^{(3)}(0)\displaystyle\frac{x^3}{3!}+f^{(4)}(0)\displaystyle\frac{x^4}{4!}+f^{(5)}(0)\displaystyle\frac{x^5}{5!}+R_6(x)$

with

$\bf R_6(x)=f^{(6)}(c)\displaystyle\frac{x^6}{6!}$

for some c in the interval (-x, x)

In the particular case f

f(x)=cos(x)

we have

$\bf f'(x)=-sin(x)\\f''(x)=-cos(x)\\f^{(3)}(x)=sin(x)\\f^{(4)}(x)=cos(x)\\f^{(5)}(x)=-sin(x)\\f^{(6)}(x)=-cos(x)$

therefore

$\bf f'(x)=-sin(0)=0\\f''(0)=-cos(0)=-1\\f^{(3)}(0)=sin(0)=0\\f^{(4)}(0)=cos(0)=1\\f^{(5)}(0)=-sin(0)=0$

and the polynomial approximation of T5(x) of cos(x) would be

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

In order to find all the values of x for which this approximation is within 0.002652 of the right answer, we notice that

$\bf R_6(x)=-cos(c)\displaystyle\frac{x^6}{6!}$

for some c in (-x,x). So

$\bf |R_6(x)|\leq|\displaystyle\frac{x^6}{6!}|=\displaystyle\frac{|x|^6}{6!}$

and we must find the values of x for which

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652$

Working this inequality out, we find

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652\Rightarrow |x|^6\leq1.90944\Rightarrow\\\\\Rightarrow |x|\leq\sqrt[6]{1.90944}\Rightarrow |x|\leq1.113826815$

Therefore the polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

8 0

3 years ago

Abbie babysits on the weekends. She charges $10 for the first hour and $6 for each

Dvinal [7]

Answer:

5 hours

Step-by-step explanation:

34-10(first hour) is 24

24/6(price per additonal hour)=4

so theres four additional hours and the one OG hour so its 5 hours total

8 0

3 years ago

Matteo is following this recipe to make a cake.

Fofino [41]

Answer:

30 ounces of butter

25 ounces of sugar

35 ounces of flour

15 eggs

10 tbps of baking powder

Step-by-step explanation:

All you do is multiple each quantity by 5 I think

we are learning about this in school but check the web to see if it is correct

4 0

3 years ago