Hello,
let's assume a the width, b the heigth.
sin 30°=a/26=1/2==>a=26/2=13 (in)
cos 30°=b/26=√3/2==>b=26*√3 / 2=13√3≈22.51666.... (in)
Answer:
12+xh
Step-by-step explanation:
Answer: The distance of Observer A from the radio antenna is what fraction of the distance of Observer B from the radio antenna?
It is 1/4.
Step-by-step explanation:
We know that the intensity of electromagnetic waves decreases with the radius squared, this means that we can write a simple relation as:
Intensity(r) = A/r^2
Observer A measures 16 the intensity of observer B.
if Ia is the intensity that observer A measures and Ib is the intensity that observer B measures, we have that:
Ia = 16Ib
A/(ra)^2 = 16*A/(rb)^2
1/(ra)^2 = 16/(rb)^2
rb^2 = 16*ra^2
and we know that 16 = 4*4 = 4^2
rb^2 = (4*ra)^2
then rb = 4*ra
this means that the distance between observer B and the antenna is equal to 4 times the distance between observer A and the antenna.
The fraction is ra = rb/4
The distance of
Observer A from the radio antenna is what fraction of the distance of Observer B from the radio antenna?
It is 1/4.
There's a simple formula for the area of an ellipse: pi*a*b, where a and b are , half the lengths of the long axis and the short axis respectively.
Here, A = pi*(12 ft)(4 ft) = 48 pi ft^2, or about 150.8 ft^2.
