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Feliz [49]
3 years ago
13

Using the matrix solver on your calculator, find the solution to the system of equations shown below.3x - 5y = 162x - 7y = 7 bra

inly
Mathematics
1 answer:
kolezko [41]3 years ago
4 0

Answer: x=7 , y=1

Step-by-step explanation:

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Pleaseeee pleaseee help mee with precal...One root of 2x2 + 8x + c = 0 is r1 = 1 + √5. Find r2.
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If a root is a+√b then another is a-√b    because of quadatic formula



r2=1-√5
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4 years ago
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What is true about the completely simplified sum of the polynomials 3x^2y^2-2xy^5 and -3x^2y^2 + 3x^2y^2 + 3x^4y?
WINSTONCH [101]

Given:

The polynomials are:

3x^2y^2-2xy^5

-3x^2y^2+3x^2y^2+3x^4y

To find:

The completely simplified sum of the polynomials.

Solution:

We have,

3x^2y^2-2xy^5

-3x^2y^2+3x^2y^2+3x^4y

The sum of given polynomials is:

Sum=3x^2y^2-2xy^5-3x^2y^2+3x^2y^2+3x^4y

Sum=-2xy^5+3x^4y+3x^2y^2

Therefore, the sum of the given polynomials is -2xy^5+3x^4y+3x^2y^2. It is a polynomial with degree 6 and leading coefficient -2.

5 0
3 years ago
The amount of radioactive uranium changes with time. The abscissas and ordinates of the points given are the time and amoung of
kakasveta [241]
The answer is <span>A. f(t) = 100(0.25)t
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This may be solved by inserting all points to your answer and sseeing if they work. Since <span>A. f(t) = 100(0.25)t fits with all points, this best represents the relationship between f(t) and t.
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Thank you for posting your question. I hope you found what you were after. Please feel free to ask me more.

 

 

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4 0
3 years ago
An elevator containing five people can stop at any of seven floors. What is the probability that no two people exit at the same
elena-s [515]

Answer:

Approximately 0.15 (360 / 2401.) (Assume that the choices of the 5 passengers are independent. Also assume that the probability that a passenger chooses a particular floor is the same for all 7 floors.)

Step-by-step explanation:

If there is no requirement that no two passengers exit at the same floor, each of these 5 passenger could choose from any one of the 7 floors. There would be a total of 7 \times 7 \times 7 \times 7 \times 7 = 7^{5} unique ways for these 5\! passengers to exit the elevator.

Assume that no two passengers are allowed to exit at the same floor.

The first passenger could choose from any of the 7 floors.

However, the second passenger would not be able to choose the same floor as the first passenger. Thus, the second passenger would have to choose from only (7 - 1) = 6 floors.

Likewise, the third passenger would have to choose from only (7 - 2) = 5 floors.

Thus, under the requirement that no two passenger could exit at the same floor, there would be only (7 \times 6 \times 5 \times 4 \times 3) unique ways for these two passengers to exit the elevator.

By the assumption that the choices of the passengers are independent and uniform across the 7 floors. Each of these 7^{5} combinations would be equally likely.

Thus, the probability that the chosen combination satisfies the requirements (no two passengers exit at the same floor) would be:

\begin{aligned}\frac{(7 \times 6 \times 5 \times 4 \times 3)}{7^{5}} \approx 0.15\end{aligned}.

5 0
2 years ago
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