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Mkey [24]
3 years ago
14

5a^2-25a Select the method(s) of factoring that must be used to factor the following polynomial (select all that apply): Differe

nce of Squares, Product Sum Factoring, Greatest Common Factor (GCF), Bottoms Up Factoring, Cannot be factored.
Mathematics
1 answer:
aleksley [76]3 years ago
7 0

We are given : 5a^2-25a

Please note: We always check Greatest Common Factor (GCF) first when factoring a polynomial.

If Greatest Common Factor (GCF) exist we factor out GCF.

In the given polynomial, we can see that greatest common factor of 5a^2 and 25a is 5a.

So, we would factor out GCF 5a first.

In order to factor out GCF, we need to divide all terms of the polynomila by GCF we got.

If we factor out 5a from 5a^2 -25a, we need to divide 5a^2 and -25a by 5a.

On dividing 5a^2 by 5a we get a and

on dividing -25a by 5a we get -5.

Therefore, on factoring out 5a, we get

5a(a-5).

Therefore, we use Greatest Common Factor (GCF) method of factoring.

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Evaluate each expression<br> 6! =<br> 3! • 2=<br> 31
Airida [17]
<h2><u>N-FACTORIAL!</u></h2>

<h3>\mathbb{  \color{brown} \: PROBLEM  }  \:   \:  \bold{{ \color{brown}{1}}} :</h3>

\mathcal{SOLUTION: }

  • \:   \bold{ \red{6!}= 6×5×4×3×2×1= \boxed{ \bold{ \blue{720}}}}

Therefore, <u>the value of 6! is 720</u>.

━┈─────────────────────┈━

<h3>\mathbb{  \color{brown} \: PROBLEM  }  \:   \:  \bold{{ \color{brown}{2}}} :</h3>

\mathcal{SOLUTION: }

  • \bold{3!  \cdot 2! }\implies  \bold{(3×2×1)  \cdot( 2×1 )}

  • \:   \: \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \implies \: \bold{ 6  \times 2} =  \boxed{ \bold{ \blue{12}}}

Therefore, <u>the value of the given expression is 12.</u>

━┈─────────────────────┈━

<h3><u>EXPLANATION</u><u>:</u></h3>
  • The mathematical symbol n! is read as "n factorial". The exclamation point "!" is read as factorial. And please remember or take note that 0! is equal to 1, and 1! is also equal to 1.

_______________∞_______________

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2 years ago
How to find the indicated probability to this problem? This is a homework practice. Show your work. Thanks!
AlladinOne [14]

You want to find P(\text{no exercise}\mid\text{woman}); that is, given that you randomly choose from the pool of women, the probability that she does not exercise.

By definition of conditional probability,

P(\text{no exercise}\mid\text{woman})=\dfrac{P(\text{no exercise AND woman})}{P(\text{woman})}

496 of the total 1026 people are woman, and 341 of the 1026 people are women and do not exercise, so

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A simpler way of doing this is to look at what's called the marginal distribution of women in the table. Basically this comes down to ignoring all but the data pertaining to the women. There's a total of 496 women, and 341 of them do not exercise. So the probability that a given woman does not exercise is 341/496.

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Step-by-step explanation:


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Someone help me please???
NeTakaya
Im thinking the 3rd one . I’m not 100 percent sure.
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