<span>3x+4y=8
4y = -3x + 8; slope = -3
</span><span>parallel lines, slope is the same so slope = -3
</span><span>passes through (2,-5)
y = mx + b
b = y - mx
b = -5 - (-3)(2)
b = -5 + 6
b = 1
equation
y = -3x +1
hope it helps</span>
Given that In Playball, the player picks a single letter from A to Tand a single digit from 0 to 9. If both the letter and the digit match the letter and the
digit picked on that day, the player wins $280, changed to 250.
Game cost = 1 dollar
There are 20 alphabets and 9 digits
No of ways to select at random =
No of ways to win = 1
So probability to win =
Since he has to pay 1 dollar whether he wins or not
PDF of X amount net won or net value would be
X -1 249 Total
p 1
xp -
Expected value = 0.38889
The option are missing in the question. The options are :
A. P = 2, a = 1
B. 
C. 
D. P = 2, a = 3
Solution :
The given function is 
So for the function to be an exponential growth, a should be a positive number and should be larger than 1. If it less than 1 or a fraction, then it is a decay. If the value of a is negative, then it would be between positive and negative alternately.
When the four option being substituted in the function, we get
A). It is a constant function since 
B). Here, the value of a is a fraction which is less than 1, so it is a decay function. 
C). It is a constant function since the value of a is 1.
D). Here a = 3. So substituting, as the value of x increases by 1, the value of the function, f(x) increases by 3 times.
Therefore, option (D). represents an exponential function.
36 is B
37 is H
Do not quote me on this, but I think the first inequality x= any number over 15
And the second one is r=4
Answer:
-5
Step-by-step explanation:
Given the two box plots showing the number of seconds the students completes the 50-meter-dash race before and after the program, we are to determine the difference between the median value of seconds before and after the program.
Median in a box plot is represented by the vertical line that divides the rectangular box in a box plot.
Thus, the median before the program = 15 seconds
The Median after the program = 10 seconds
The median change = 10 - 15 = -5 seconds.
This means, after the program, most of the students now finish the 50-meter-dash faster, about 5 seconds less the former seconds used before the program.
